Answer:
64567000000 nanolitres
Explanation:
Base 10 decimal system: 1 milli = 1000000 nano
We simply multiply 64,567 millilitres by 1000000 to get our number in nanolitres:
64567(1000000) = 64567000000 nanolitres
Explanation:
1: fluorine to form lithium fluoride
2:bcos covalent bond exists btw two non metals
3: bcos it is d combination of two or more elements nd elements r substances
4: for sbustances we hv flame test nd splint test
ionic compounds are held by strong electrostatic forces of attraction
The term Big Bang defines that the Universe has expanded from the ancient hot and thick primary situation at some fixed time in the past.
Big Bang theory refers to the origin of the Universe. In the beginning, universe is very heavy and small hot ball of matter. It was a point no bigger than the head of a pin when all the things squished with each other and universe is expanded with huge explosion of energy. Due to expansion, it is cooled and results in the formation of Stars and galaxies. After sometime, atoms formed like helium and hydrogen.
Thus, statement (1), (3) and (4) is correct whereas statement (2) and (5) is incorrect.
Chromium is a fairly active metal. It does not react with water, but reacts with most acids. It combines with oxygen at room temperature to form chromium oxide (Cr 2 O 3 ). Chromium oxide forms a thin layer on the surface of the metal, protecting it from further corrosion (rusting).
Answer:
The correct answer is: Serine, Histidine, Aspartate
Explanation:
The catalytic triad of an enzyme is composed of three aminoacid residues which are the most important for its catalytic activity. They are located in the catalytic site of the enzyme. In the case of chymotrypsin- a serine protease, the catalytic triad is composed by serine, histidine and aspartate (Ser-His-Asp). Serine proteases hydrolyse peptidic bonds in proteins and peptides. To do that, the histidine-which interacts with the aspartate by a hydrogen bond so its pKa increases- take a proton from the serine. Thus, deprotonated serine is able to attack the peptide bond and to perform hydrolysis.
