how much hydrogen will be released during the interaction of potassium weighing 8 grams with hydrochloric acid

Chemistry

1 answer:

krek1111 [17]2 years ago

4 0

Answer:

With an understanding of the ideal gas laws, it is now possible to apply these principles to chemical stoichiometry problems. For example, zinc metal and hydrochloric acid (hydrogen chloride dissolved in water) react to form zinc (II) chloride and hydrogen gas according to the equation shown below:

2 HCl (aq) + Zn (s) → ZnCl2 (aq) + H2 (g)

Explanation:

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Wat is significant figures

Sav [38]

Answer:

0.052301 km have 5 significant figure
400 cm have 1 significant figure
50.0 m have 3 significant figure
4500.01 ml have 6 significant figure

Explanation:

According to rules of significant figure

0.052301 km have 5 significant figure:

Zero to the left of the first non zero digit not significant.
Zero between the non zero digits are significant.

400 cm have 1 significant figure:

Trailing zeros are not significant in numbers without decimal points.

50.0 m have 3 significant figure:

Trailing zeros are significant in numbers when there is decimal points.

4500.01 ml have 6 significant figure:

Zero between the non zero digits are significant.

4 0

3 years ago

What is the pH of a mixture of 0.042 M NaH2PO4 and 0.058 M Na2HPO4? Hint: The pKa of phosphate is 6.86.

AlekseyPX

Answer:

The pH value of the mixture will be 7.00

Explanation:

Mono and disodium hydrogen phosphate mixture act as a buffer to maintain pH value around 7. Henderson–Hasselbalch equation is used to determine the pH value of a buffer mixture, which is mathematically expressed as,

$pH=pK_{a} + log(\frac{[Base]}{[Acid]})$

According to the given conditions, the equation will become as follow

$pH=pK_{a} + log(\frac{[Na_{2}HPO_{4} ]}{[NaH_{2}PO_{4}]})$

The base and acid are assigned by observing the pKa values of both the compounds; smaller value means more acidic. NaH₂PO₄ has a pKa value of 6.86, while Na₂HPO₄ has a pKa value of 12.32 (not given, but it's a constant). Another more easy way is to the count the acidic hydrogen in the molecular formula; the compound with more acidic hydrogens will be assigned acidic and vice versa.

Placing all the given data we obtain,

$pH=6.86 + log(\frac{0.058}{0.042})$