<h3>
Answer:</h3>
TRUE- The surface tension of CH3Br is greater than the surface tension of CH3Cl.
FALSE-Water forms spherical drops on wax because the surface tension of water is greater than the adhesive forces between wax and water.
<h3>
Explanation:</h3>
- The statement that, the surface tension of CH3Br is greater than the surface tension of CH3Cl is true.
- This is because of the fact that CH₃Br has more molar mass compared to CH₃Cl. Additionally, CH₃Br has greater dispersion forces and is more polarizable thus having greater surface tension compared to CH₃Cl.
- The statement that "Water forms spherical drops on wax because the surface tension of water is greater than the adhesive forces between wax and water" is FALSE.
- We would correct it by saying, Water forms spherical drops on wax because the cohesive force of water is greater than the adhesive forces between wax and water.
- Cohesive forces are forces of attraction between molecules or particles of the same type while adhesive forces is a force of attraction between molecules of different type.
Answer:
water and oxygen
Explanation:
this is because
iron + water + oxygen ----> hydrated iron (III) oxide (which is rust in lame terms )
hope this helps
please mark it brainliest
Spinach and broccoli are high in Iron. The respiratory system needs constant supplies of iron to maintain healthy blood cells. Not having enough Iron can lead to low numbers of red blood cells, without red blood cells not enough blood will flow to organs, causing iron deficient anemia.
Hope this helps!
Answer:
The percent ionization is 0,16%
Explanation:
The percent ionization is defined as the number of ions that exist in a substance.
![PI=\frac{[A-]}{[HA]} x100](https://tex.z-dn.net/?f=PI%3D%5Cfrac%7B%5BA-%5D%7D%7B%5BHA%5D%7D%20x100)
First, we find the [A-] using the ka equation
HA ⇄ 
[H+] = [A-]
![Ka=\frac{[H+][A-]}{[HA]}\\ \\](https://tex.z-dn.net/?f=Ka%3D%5Cfrac%7B%5BH%2B%5D%5BA-%5D%7D%7B%5BHA%5D%7D%5C%5C%20%5C%5C)
since the ionization constant is very small we can assume that the final concentration of [HA] is the same
![Ka=\frac{[H+]^{2} }{[HA]} \\\\](https://tex.z-dn.net/?f=Ka%3D%5Cfrac%7B%5BH%2B%5D%5E%7B2%7D%20%7D%7B%5BHA%5D%7D%20%5C%5C%5C%5C)
![[H+]=\sqrt[2]{Ka.[HA]} \\\\](https://tex.z-dn.net/?f=%5BH%2B%5D%3D%5Csqrt%5B2%5D%7BKa.%5BHA%5D%7D%20%5C%5C%5C%5C)
![[H+] =\sqrt{(2,610^{-7} )(0,1)} = 1,61210^{-4}](https://tex.z-dn.net/?f=%5BH%2B%5D%20%3D%5Csqrt%7B%282%2C610%5E%7B-7%7D%20%29%280%2C1%29%7D%20%20%3D%201%2C61210%5E%7B-4%7D)
Now we calculate the percent ionization using these values
PI=0,16%
