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2 years ago

what describes the equivalence point on a graph of pH versus the amount of titrant added to a solution

Chemistry

1 answer:

olga_2 [115]2 years ago

6 0

Answer:

Titrant and analyte is a pair of acid and base. ... Equivalence point: point in titration at which the amount of titrant added is just enough to completely neutralize the analyte solution. At the equivalence point in an acid-base titration, moles of base = moles of acid and the solution only contains salt and water.

Explanation:

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What is the molality of a solution containing 10.0 G of NA2 S04 and 1000.0 G of water

galina1969 [7]

Explanation:

1 literThe total of water is equal to 1000.0 g of water

we need to find the molality of a solution containing 10.0 g of dissolved in Na₂S0₄1000.0 g of water

1. For that find the molar mass

Na: 2 x 22.99= 45.98

S: 32.07

O: 4 x 16= 64

The total molar mass is 142.05

We have to find the number of moles, y

To find the number of moles divide 10.0g by 142.05 g/mol.

So the number of moles is 0.0704 moles.

For the molarity, you need the number of moles divided by the volume. So, 0.0704 mol/1 L.

The molarity would end up being 0.0704 M

The molality of a solution containing 10.0 g of Na2SO4 dissolved in 1000.0 g of water is 0.0704 Mliter

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2 years ago

you are on spring break and you won a bunch of balloons at a carnival in the mountains of Georgie. You are now driving back to F

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3 years ago

What is the most common way atoms combine

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Atoms combine<span> by forming chemical bonds</span>

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3 years ago

The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula: E = R_y/n^2 In this equation R_y stands

Katarina [22]

Answer:

The wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron for the given energy levels is $5.23\times 10^{-5} m$

Explanation:

Given :

The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula:

$E=\frac{R_y}{n^2}$

$R_y=2.18\times 10^{-18} J$ = Rydberg energy

n = principal quantum number of the orbital

Energy of 11th orbit = $E_{11}$

$E_{11}=\frac{2.18\times 10^{-18} J}{11^2}=1.80\times 10^{-20} J$

Energy of 10th orbit = $E_{10}$

$E_{10}=\frac{2.18\times 10^{-18} J}{10^2}=2.18\times 10^{-20} J$

Energy difference between both the levels will corresponds to the energy of the wavelength of the line which can be calculated by using Planck's equation.

$E'=E_{10}-E_{11}=2.18\times 10^{-20} J-1.80\times 10^{-20} J$

$=E'=0.38\times 10^{-20} J$

$\lambda =\frac{hc}{E'}$ (Planck's' equation)

$\lambda = \frac{6.626\times 10^{-34} Js\times 3\times 10^8 m/s}{0.38\times 10^{-20} J}$

$\lambda = 5.2310\times 10^{-5} m\approx 5.23\times 10^{-5} m$

The wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron for the given energy levels is $5.23\times 10^{-5} m$

3 0

3 years ago

The teacher said the volume of the liquid was 500 mL when measured a student found it was 499.7 mL what is the students percent

Natalka [10]

Answer:

Explanation:

The percentage error of a certain measurement can be found by using the formula

$P(\%) = \frac{error}{actual \: \: number} \times 100\% \\$

From the question

error = 500 - 499.7 = 0.3

actual volume = 500 mL

We have

$p(\%) = \frac{0.3}{500} \times 100 \\ = \frac{3}{50} \\$

We have the final answer as

Hope this helps you

4 0

3 years ago

what describes the equivalence point on a graph of pH versus the amount of titrant added to a solution ​

what describes the equivalence point on a graph of pH versus the amount of titrant added to a solution