Answer:
the answeer is definitely silicon.
Answer:
Explanation:
Hello,
In this case, for dilution process, we can notice that the initial moles remain the same once the dilution is completed, therefore, both concentration and volume change considering:
In such a way for the given final volume, the resulting concentration is noticed to be:
This is supported by the fact that the higher the volume the lower the concentration.
Best regards.
<u>Answer:</u> The mass percent of water in the hydrated salt is 43.6 %
<u>Explanation:</u>
To calculate the mass for given number of moles, we use the equation:
Moles of water = 8 moles
Molar mass of water = 18 g/mol
Putting values in above equation, we get:
We are given:
Mass of anhydrous salt = 186.181 g
To calculate the mass percentage of water in the hydrated salt, we use the equation:
Mass of hydrated salt = [186.181 + 144]g = 330.181g
Mass of water = 144 g
Putting values in above equation, we get:
Hence, the mass percent of water in the hydrated salt is 43.6 %
Answer:
17.5609g
Explanation:
According to the question, a sample of mass 6.814 grams is added to another sample weighing 0.08753 grams. That is weight of sample 1 + weight of sample 2;
6.814 + 0.08753 = 6.90153grams
Next, the subsequent mixture is then divided into exactly 3 equal parts i.e. 6.90153grams divided by 3
= 6.90153/3
= 2.30051grams.
One of the equal parts is 2.30051grams, which is then multiplied by 7.6335 times I.e. 2.30051 × 7.6335 = 17.5609grams
Therefore, the final mass is 17.5609grams