Answer:
3.0 L of NH₃
Solution:
The equation is as follow,
N₂ + 3 H₂ → 2 NH₃
According to equation,
67.2 L (3 mole) H₂ at STP produces = 44.8 L (3 mole) of NH₃
So,
4.50 L of H₂ will produce = X L of NH₃
Solving for X,
X = (4.50 L × 44.8 L) ÷ 67.2 L
X = 3.0 L of NH₃
Answer:
n Al= 10/27( mol)- >n Al2O 3 =5/27(mol)
Explanation:
Answer:
You can fill 212 balloons.
Explanation:
First we <u>calculate the helium moles in the small cylinder</u>, using <em>PV=nRT:</em>
- P = 14300 kPa ⇒ 14300 * 0.009869 = 141.13 atm
- R = 0.082 atm·L·mol⁻¹·K⁻¹
- T = 25 °C ⇒ 25 + 273.16 = 298.16 K
141.13 atm * 2.20 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 298.16 K
Then we <u>calculate the number of moles that can fit in a single balloon</u>:
- 1.22 atm * 1.20 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 298.16 K
Finally we <u>divide the total number of available moles by the number of moles in a single balloon</u>:
- 12.70 mol / 0.0599 mol = 212.09
So the answer is that you can fill 212 balloons.
17.8 g of sodium perchlorate contains 8.73 × 10²² Na⁺ ions, 8.73 × 10²² ClO₄⁻ ions, 8.73 × 10²² Cl atoms and 3.49 × 10²³ O atoms.
First, we will convert 17.8 g of NaClO₄ to moles using its molar mass (122.44 g/mol).

Next, we will convert 0.145 moles to molecules of NaClO₄ using Avogadro's number; there are 6.02 × 10²³ molecules in 1 mole of molecules.

NaClO₄ is a strong electrolyte that dissociates according to the following equation.
NaClO₄ ⇒ Na⁺ + ClO₄⁻
The molar ratio of NaClO₄ to Na⁺ is 1:1. The number of Na⁺ in 8.73 × 10²² molecules of NaClO₄ is:

The molar ratio of NaClO₄ to ClO₄⁻ is 1:1. The number of ClO₄⁻ in 8.73 × 10²² molecules of NaClO₄ is:

The molar ratio of ClO₄⁻ to Cl is 1:1. The number of Cl in 8.73 × 10²² ions of ClO₄⁻ is:

The molar ratio of ClO₄⁻ to O is 1:1. The number of O in 8.73 × 10²² ions of ClO₄⁻ is:

17.8 g of sodium perchlorate contains 8.73 × 10²² Na⁺ ions, 8.73 × 10²² ClO₄⁻ ions, 8.73 × 10²² Cl atoms and 3.49 × 10²³ O atoms.
You can learn more Avogadro's number here: brainly.com/question/13302703
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