F=m*a=>a=F/m=10000/1267=7.89 m/s²
d=v₀t+a't²/2<=>394.6=112.5*a'=>a'=3.5
a-a'=7.89-3.5=4.39 m/s²
This difference causes friction forces
We apply the second principle of dynamics: vector: F + N + G + Ff = ma (vector vectors, I can not here)
Scalar: Ox: F-Ff = ma
Oy N-mg = 0
Ff = -ma+ F =-1267*7.89+10000=-8869+10000=1131 N
This frictional force (Ff) is opposite to the traction (F)
Answer:
The force must he apply to the sled is of F= 764.4 N.
Explanation:
m= 60 kg
g= 9.8 m/s²
μ=0.3
W= m*g
W= 588 N
Fr= μ*W
Fr= 176.4 N
F= W + Fr
F= 764.4 N
Answer:
1.17 m
Explanation:
From the question,
s₁ = vt₁/2................ Equation 1
Where s₁ = distance of the reflecting object for the first echo, v = speed of the sound in air, t₁ = time to dectect the first echo.
Given: v = 343 m/s, t = 0.0115 s
Substitute into equation 1
s₁ = (343×0.0115)/2
s₁ = 1.97 m.
Similarly,
s₂ = vt₂/2.................. Equation 2
Where s₂ = distance of the reflecting object for the second echo, t₂ = Time taken to detect the second echo
Given: v = 343 m/s, t₂ = 0.0183 s
Substitute into equation 2
s₂ = (343×0.0183)/2
s₂ = 3.14 m
The distance moved by the reflecting object from s₁ to s₂ = s₂-s₁
s₂-s₁ = (3.14-1.97) m = 1.17 m
Answer:
Action and reaction are equal but act in opposite directions
Answer:
R=V/I=6/2=3ohm
time =5minutes =5*60=300seconds
I=2A
Heat =I^2Rt=(2)^2*3*300=4*900=3600J
