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2 years ago

What is the probbability of flipping a coin 15 times and getting heads 6 times?

Mathematics

1 answer:

asambeis [7]2 years ago

3 0

Answer:

if I'm wrong let me know 25

You might be interested in

Can someone help me 17 through 28

Salsk061 [2.6K]

17) 3*5 + 4 = 19
18) 2 * 3 = 6
19) 3 * 36 + 2 * 6 + 1 = 121
20) 5 * 49 + 6 * 7 = 287
21) 6 * 64 + 6 * 8 + 6 = 438
22) 1 * 81 = 81
23) 1 * 8 + 1 * 4 = 12
24) 7 * 729 + 5 = 5108
25) 1 * 1296 + 5 * 216 + 2 * 36 = 2448
26) 1 * 16 + 1 * 2 = 18
27) 4 * 3125 + 1 * 25 + 2 * 5 + 3 = 12538

8 0

3 years ago

Question 5 pleaseeee

vovikov84 [41]

Answer:

first

Step-by-step explanation:

f(n) =56 (0.5)^(n-1)

f(1) = 56 (0.5)^0= 56*1 = 56

f(2) =56 (0.5)^1 = 56* 0.5 = 28

f(3) = 56 (0.5)^2 = 14

f(4) = 56 (0.5)^3 = 7

3 0

3 years ago

If x = 7 − p and y = 3p + 4, which of the following

Rudiy27

Answer:

y = 25 - 3x

Step-by-step explanation:

x = 7 - p ⇒ p = 7 - x

y = 3(7-x) + 4

y = 21 - 3x + 4

y = 25 - 3x

7 0

3 years ago

23.

Crazy boy [7]

Answer:

The number that cannot be the largest possible 6-digit number is;

(D) AAABCB

Step-by-step explanation:

From the question, we have;

A, B, and C = Distinct digits, therefore, A ≠ B ≠ C

The number of digits in the number to be formed = 6 digits

The number of 'A' in the number to be formed = 3

The number of 'B' in the number to be formed = 2

The number of 'C' in the number to be formed = 1

We have;

When A > B > C

The largest possible number = AAABBC

When C > A > B

The largest possible number = CAAABB

When B > A > C

The largest possible number = BBAAAC

When A > C > B

The largest possible number = AAACBB

Therefore, given that when A > B > C, the largest possible number = AAABBC, we have;

AAABBC > AAABCB, because B > C, therefore, within the tens and unit of the two 6 digit numbers, we have, BC > CB

∴ AAABBC > AAABCB and <u>AAABCB</u>, cannot be the largest possible 6-digit number

3 0

3 years ago

For a lottery game, a player must match a sequence of three repeatable numbers, ranging from 0 to 9, in exact order. With a

vampirchik [111]

Answer: $\frac{1}{1000}$

Step-by-step explanation:

For the lottery game three numbers must match in exact order

From 0 to 9 total 10 numbers are there

Therefore selecting exactly same numbers as of winner is

= $^{10}C_1\times ^{10}C_1\times ^{10}C_1$

Since numbers are repeatable therefore each time we have a choice of choosing 1 number out o 10

= $10\times 10\times 10$

Probability of winning= $\frac{1}{1000}$

8 0

4 years ago