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guapka [62]
3 years ago
11

A 3.00-g copper penny at 25.0°C drops from a height of50.0 m to the ground. (

Mathematics
1 answer:
Gnoma [55]3 years ago
6 0
The potential energy, E, of the penny is given by E=mgh.  The energy, Q, required to raise the temperature of an object by an amount ΔT is given by Q=mcΔT.  We can equate these two to get the result but we must use proper units and include the 60%:
(0.6)mgh=mcΔT
We see we can divide out the mass from each side
0.6gh=cΔT,   then 0.6gh/c=ΔT
(0.6)9.81(m/s²)50m/385(J/kg°C) = 0.7644°C
since this is the change in temperature and it started at 25°C we get
T=25.7644°C
As you can see the result does not depend on mass.  The more massive the copper object the more potential energy it will have to contribute to the heat energy, but the more stuff there will be to heat up, and the effect is that the mass cancels.
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Vadim26 [7]

Based on the calculations, the depth of tent is equal to 12 feet.

<h3>How to calculate the depth of the tent?</h3>

Based on the diagram (see attachment) and information provided, we can logically deduce the following parameters (points):

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  • Side AD is perpendicular side BC.
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Next, we would determine the height of the right-angled triangle (ADC) by applying Pythagorean theorem:

AC² = AD² + DC²

AD² = AC² - DC²

AD² = 5² - 3²

AD² = 25 - 9

AD² = 16

AD = √16

AD = 4 feet.

Also, we would determine the area of the triangle (ABC):

Area = 1/2 × b × h

<u>Where:</u>

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Substituting the given parameters into the formula, we have;

Area = 1/2 × 6 × 4

Area = 12 feet².

Depth of tent = 3 × height of ADC

Depth of tent = 3 × 4

Depth of tent = 12 feet.

Read more on area of triangle here: brainly.com/question/21917592

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