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nadya68 [22]
2 years ago
11

A wave pulse on a spring is 5.40 cm high and oriented upward. This pulse meets another pulse of the same shape which is 1.10 cm

high but oriented downward.
At the moment when the two pulses come together, what is the amplitude of the resulting pulse? Note: if the pulse is oriented upward, make its amplitude positive. If it is oriented downward, make its amplitude negative.
Physics
1 answer:
Ghella [55]2 years ago
3 0

The resulting positive amplitude of the two waves after the superimposition is 4.30 cm.

<h3>Amplitude of the waves</h3>

The amplitude of the waves is the maximum displacement of the wave. This is the vertical position of the wave measured from the zero origin.

After the superimposition of the two similar waves, the resulting amplitude will be less than the initial amplitude of the wave with the highest vertical height since the superimposition creates destructive interference.

Resulting amplitude of the two waves is calculated as;

A = 5.4 cm - 1.10 cm

A = 4.30 cm

Thus, the resulting positive amplitude of the two waves after the superimposition is 4.30 cm.

Learn more about amplitude of waves here: brainly.com/question/25699025

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Explanation:

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t is the time

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The two objects in the problem have same initial velocity, u = 0 (since they start from rest), so we can rewrite the equation as

d=\frac{1}{2}at^2

We see that the distance covered is proportional to the square of the time. In this problem, the two objects X and Y have same acceleration, but object X accelerates for twice the time: since d \propto t^2, this means that the distance covered by X will be 2^2 = 4 times higher that the distance covered by object Y.

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Por que el movimiento de un auto que recorre una pista circular ni es M.R.U.V​
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Answer:

Salta al contenido principal

Contenido principal

Movimiento rectilíneo uniforme (MRU)

Movimiento Rectilíneo

Movimiento rectilíneo uniforme (MRU)

Imagina que eres un astronauta en la Estación Espacial Internacional. Estás arreglando unos paneles solares averiados, cuando de pronto, al presionar, tu destornillador sale disparado de tus manos. Si no lo atrapas a tiempo, el destornillador estará viajando por el espacio en línea recta y a velocidad constante, a menos que algo se interponga en su camino. Esto sucede porque la herramienta se mueve con movimiento rectilíneo uniforme, o MRU.

Foto de la Estación Espacial Internacional

Foto de la Estación Espacial Internacional

Estación Epacial Internacional orbitando nuestro planeta. Créditos: International Space Station orbiting above earth de la National Reconnaissance Office.

El MRU se define el movimiento en el cual un objeto se desplaza en línea recta, en una sola dirección, recorriendo distancias iguales en el mismo intervalo de tiempo, manteniendo en todo su movimiento una velocidad constante y sin aceleración.

Recuerda que la velocidad es un vector, entonces, al ser constante, no varía ni su magnitud, ni su dirección de movimiento.

Condiciones del MRU

Para que un cuerpo esté en MRU, es necesario que se cumpla la siguiente relación:

t−t

0

x−x

0

Constante

Donde

xxx: es la posición en el espacio y

ttt: es el tiempo.

De esta condición, llegamos a la ecuación del MRU:

x = x_0 + v(t-t_0)x=x

0

+v(t−t

0

)x, equals, x, start subscript, 0, end subscript, plus, v, left parenthesis, t, minus, t, start subscript, 0, end subscript, right parenthesis

Donde:

\Large x_0x

0

x, start subscript, 0, end subscript: posición en el instante \Large t_0t

0

t, start subscript, 0, end subscript

\Large xxx: Posición en el instante \Large ttt

Esto quiere decir que si conocemos la posición x_0x

0

x, start subscript, 0, end subscript en el instante t_0t

0

t, start subscript, 0, end subscript y sabemos cuál es la de la velocidad vvv, podremos conocer la posición xxx en cualquier instante ttt.

¡No olvides fijarte bien en las unidades que utilizas y de convertirlas si es necesario!

Veamos un ejemplo:

Imagínate que has programado un carro robótico para que tenga una velocidad constante ¿Puedes calcular a qué distancia desde el punto de partida estará luego de 30\text{ s}30 s30, start text, space, s, end text?

Tienes los siguientes datos:

v

x

0

t

0

t

=10 m/s

=0 m

=0 s

=30 s

Explanation:

espero y esto te ayude

5 0
3 years ago
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