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nadya68 [22]
2 years ago
11

A wave pulse on a spring is 5.40 cm high and oriented upward. This pulse meets another pulse of the same shape which is 1.10 cm

high but oriented downward.
At the moment when the two pulses come together, what is the amplitude of the resulting pulse? Note: if the pulse is oriented upward, make its amplitude positive. If it is oriented downward, make its amplitude negative.
Physics
1 answer:
Ghella [55]2 years ago
3 0

The resulting positive amplitude of the two waves after the superimposition is 4.30 cm.

<h3>Amplitude of the waves</h3>

The amplitude of the waves is the maximum displacement of the wave. This is the vertical position of the wave measured from the zero origin.

After the superimposition of the two similar waves, the resulting amplitude will be less than the initial amplitude of the wave with the highest vertical height since the superimposition creates destructive interference.

Resulting amplitude of the two waves is calculated as;

A = 5.4 cm - 1.10 cm

A = 4.30 cm

Thus, the resulting positive amplitude of the two waves after the superimposition is 4.30 cm.

Learn more about amplitude of waves here: brainly.com/question/25699025

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Answer:

E) are almost circular, with low eccentricities.

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The square of the period of a planet will be proportional to the cube of the semi-major axis of its orbit (Kepler's third law).

T^{2} = a^{3}

Where T is the period of revolution and a is the semi-major axis.

Planets orbit around the Sun in an ellipse with the Sun in one of the focus. Because of that, it is not possible to the Sun to be at the center of the orbit, as the statement on option "C" says.

However, those orbits have low eccentricities (remember that an eccentricity = 0 corresponds to a circle)

In some moments of their orbit, planets will be closer to the Sun (known as perihelion). According with Kepler's second law to complete the same area in the same time, they have to speed up at their perihelion and slow down at their aphelion (point farther from the Sun in their orbit).

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Answer:

B) 3.50 m/s

Explanation:

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Finally, we calculate how fast is the child moving:

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