Answer:
q = 2,95 10-6 C
Explanation:
The magnetic force on a particle is described by the equation
F = q v x B
Where bold indicate vectors
Let's make the vector product
vxB =
v x B = 1.20 106 [i ^ (4 0.130) - j ^ (3 0.130)]
vx B = 1.20 106 [0.52 i ^ - 0.39j ^]
As they give us the force module, let's use Pythagoras' theorem,
|v xB | =1.20 10⁶ √( 0.52² + 0.39²)
|v x B| = 1.20 10⁶ 0.65
v xB = 0.78 10⁶
Let's replace and calculate
2.30 = q 0.78 10⁶
q = 2.3 / 0.78 106
q = 2,95 10-6 C
The average kinetic energy of an atom in helium gas at temperature T is given by,
K.E=
here, K is botzmann constant =1.38×10⁻²³ m² kg s⁻² K⁻¹
Given, K.E= 6.21×10⁻²¹ J
Substituting the values,
T= 300 K
Therefore, at temperature 300 K the average kinetic energy of the atom in helium gas is 6.21×10⁻²¹ J.
Answer:
Explanation:
From the question we are told that
The number of turns is
The radius is
The position from the center consider is x = 3.45 cm = 0.0345 m
The induced emf is
Generally according to Gauss law
=>
Where A is the cross-sectional area of the solenoid which is mathematically represented as
=>
=> ggl;
Here is the permeability of free space with value
=>
=>