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Licemer1 [7]
2 years ago
13

What is the most commonly preferred pH range for soil?

Chemistry
2 answers:
Semenov [28]2 years ago
7 0

Answer:

6.2 to 7.0

Explanation:

The “ideal” soil pH is close to neutral, and neutral soils are considered to fall within a range from a slightly acidic pH of 6.2-6.5 to slightly alkaline pH of 7.0-7.5. It has been determined that most plant nutrients are optimally available to plants within this 6.5 to 7.5 pH range, plus this range of pH is generally very compatible to plant root growth.

:-befrank

Tems11 [23]2 years ago
3 0

Answer:

Between 5.5 to 7.5

The optimum pH range for most plants is between 5.5 and 7.5

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Increasing which factor will cause the gravitational force between two objects to decrease?
Drupady [299]

Answer:

mass increase!

Explanation:

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5 0
2 years ago
Determine the energy of 1.70 mol of photons for each of the following kinds of light. (Assume three significant figures.)PART A
BabaBlast [244]

<u>Answer:</u>

<u>For A:</u> The energy of the given amount of photons for infrared radiation is 1.271\times 10^5J

<u>For B:</u> The energy of the given amount of photons for infrared radiation is 4.026\times 10^5J

<u>For C:</u> The energy of the given amount of photons for infrared radiation is 1.355\times 10^6J

<u>Explanation:</u>

The relationship between energy and frequency is given by Planck's equation, which is:

E=n\rimes N_A\times \frac{hc}{\lambda}        ......(1)

where,

h = Planck's constant  = 6.62\times 10^{-34}Js

E = energy of the light

c = speed of light = 3\times 10^8m/s

\lambda = wavelength of light

N_A = Avogadro's number = 6.022\times 10^{23}

n = number of moles of photons = 1.70 moles

Conversion factor used:  1m=10^9nm

  • <u>For A:</u>

Wavelength of infrared radiation = 1600nm=1.6\times 10^6m

Putting values in equation 1, we get:

E=1.7\times 6.022\times 10^{23}\times \frac{6.62\times 10^{-34}\times 3\times 10^8}{1.6\times 10^{-6}}\\\\E=1.271\times 10^5J

Hence, the energy of the given amount of photons for infrared radiation is 1.271\times 10^5J

  • <u>For B:</u>

Wavelength of visible light = 505nm=5.05\times 10^7m

Putting values in equation 1, we get:

E=1.7\times 6.022\times 10^{23}\times \frac{6.62\times 10^{-34}\times 3\times 10^8}{5.05\times 10^{-7}}\\\\E=4.026\times 10^5J

Hence, the energy of the given amount of photons for infrared radiation is 4.026\times 10^5J

  • <u>For C:</u>

Wavelength of ultraviolet radiation = 150nm=1.5\times 10^7m

Putting values in equation 1, we get:

E=1.7\times 6.022\times 10^{23}\times \frac{6.62\times 10^{-34}\times 3\times 10^8}{1.5\times 10^{-7}}\\\\E=1.355\times 10^6J

Hence, the energy of the given amount of photons for infrared radiation is 1.355\times 10^6J

3 0
4 years ago
QUICKEST GETS BRAINLIEST AND 7 POINTS
KonstantinChe [14]
A positive solid sphere with electrons dispersed.
6 0
3 years ago
What is the molarity of the two solutions <br> 0.150 mol of NaOH in 1.80 L of solution
padilas [110]
1 mole of MgS = 24.3 + 32.1 = 56.4 g

35.1 g MgS x 1 mol / 56.4 g = 0.622 mol

M = 0.622 mol / 0.835 L = 0.745 mol/L
4 0
4 years ago
For the wild type (unmutated) enzyme, you measure a rate of p-nitrophenol release by the change in absorbance at 405 nm (for the
Aleks04 [339]

Answer:

1.2x10⁻⁵M = Concentration of the product released

Explanation:

Lambert-Beer's law states the absorbance of a solution is directly proportional to its concentration. The equation is:

A = E*b*C

<em>Where A is the absotbance of the solution: 0.216</em>

<em>E is the extinction coefficient = 18000M⁻¹cm⁻¹</em>

<em>b is patelength = 1cm</em>

<em>C is concentration of the solution</em>

<em />

Replacing:

0.216 = 18000M⁻¹cm⁻¹*1cm*C

<h3>1.2x10⁻⁵M = Concentration of the product released</h3>
4 0
3 years ago
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