The question is incomplete, here is the complete question:
Consider the reaction 
Initially, ![[NH_3(g)]=[O_2(g)]](https://tex.z-dn.net/?f=%5BNH_3%28g%29%5D%3D%5BO_2%28g%29%5D)
= 3.60 M; at equilibrium ![[N_2O_4(g)]=0.60M](https://tex.z-dn.net/?f=%5BN_2O_4%28g%29%5D%3D0.60M)
. Calculate the equilibrium concentration for 
<u>Answer:</u> The equilibrium concentration of ammonia is 2.8 M
<u>Explanation:</u>
We are given:
Initial concentration of ![[NH_3(g)]](https://tex.z-dn.net/?f=%5BNH_3%28g%29%5D)
= 3.60 M
Initial concentration of ![[O_2(g)]](https://tex.z-dn.net/?f=%5BO_2%28g%29%5D)
= 3.60 M
For the given chemical equation:
Initial: 3.60 3.60
At eqllm: 3.60-4x 3.60-7x 2x 6x
We are given:
Equilibrium concentration of ![[N_2O_4(g)]](https://tex.z-dn.net/?f=%5BN_2O_4%28g%29%5D)
= 0.60 M
Evaluating the value of 'x'
So, equilibrium concentration of 
Hence, the equilibrium concentration of ammonia is 2.8 M
I think there are 3
1) lack of membrane-bound organelles
2) unicellular
3) small (usually microscopic) size.
Explanation:
If copper sulphate crystals are added to water then, the particles of copper sulphate crystals loses attraction between them and starts moving continuously and gets mixed up with water. It is called 'hydrated copper sulphate solution which is having a blue colour.
1 mol ------- 6,02·10²³
X ------------ 3,98·10²³
X = 3,98·10²³/<span>6,02·10²³
<u>X= 0,6611</u> moles of oxygen
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:)</span>
Answer:
The answer to your question is the first choice
Explanation:
Perishable food is food with a limited shelf life if it is not refrigerated. Also, it is considered a perishable food the one that goes bad quickly when it leaves the fridge.
Example of perishable food:
Vegetables, Fruits, Meat, Fish, Milk, Yogurt, etc.
