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Vsevolod [243]
2 years ago
6

H H H O H O N C C N C C H O H H O H H C H H H ALANINE GLYCINE

Physics
1 answer:
Trava [24]2 years ago
6 0
i’m not 100 percent sure but I need points to ask questions good luck th
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a 15kg television sits on a shelf at a height of 0.3 m how much gravitational potential energy is added to the television when i
DedPeter [7]

Answer:

<h2>103 Joules</h2>

Explanation:

In this problem we are required to find the potential energy possessed by the television

Given data

mass of television m = 15 kg

height  added above the ground, h= 1-0.3 = 0.7 m

acceleration due to gravity g = 9.81 m/s^2

apply the formula for potential energy we have

P.E= m*g*h

P.E = 15*9.81*0.7 = 103 Joules

7 0
3 years ago
How is the L-section filter useful at both low and high frequencies?​
Gnom [1K]

Answer: High pass filters, and in particular LC high pass filters are used in many RF applications where they block the lower frequencies and allow through higher frequency signals. Typically LC filters are used for the higher radio frequencies where active filters are not so manageable, and inductors more appropriate.

8 0
3 years ago
Read 2 more answers
ln the constellation of Orion, you can see a group of stars and other objects that appear in the shape of a sword. Ln the middle
bagirrra123 [75]

Answer:

Nebula

Explanation:

 Given that in the constellation of Orion, you can see a group of stars and other objects that appear in the shape of a sword. Ln the middle of the sword, a bright "fuzzy star" appears. Astronomers looking at this object through telescopes refer to it as a "stellar nursery." Another name for this object is called NEBULA.

The space where new stars are forming anew is known as nebulae

7 0
3 years ago
Car A hits car B (initially at rest and of equal mass) frombehind while going 35 m/s. Immediately after the collision, car Bmove
kolezko [41]

Answer:

The fraction of kinetic energy lost in the collision in term of the initial energy is 0.49.

Explanation:

As the final and initial velocities are known it is possible then the kinetic energy is possible to calculate for each instant.

By definition, the kinetic energy is:

k = 0.5*mV^2

Expressing the initial and final kinetic energy for cars A and B:

ki=0.5*maVa_{i}^2+0.5*mbVb_{i}^2

kf=0.5*maVa_{f}^2+0.5*mbVb_{f}^2

Since the masses are equals:

m=ma=mb

For the known velocities, the kinetics energies result:

ki=0.5*mVa_{i}^2

ki=0.5*m(35 m/s)^2=612.5m^2/s^2*m

kf=0.5*mbVb_{f}^2

kf=0.5*m(25 m/s)^2=312.5m^2/s^2*m

The lost energy in the collision is the difference between the initial and final kinectic energies:

kl=ki-kf

kl = 612.5m^2/s^2*m-312.5 m^2/s^2*m=300 m^2/s^2*m

Finally the relation between the lost and the initial kinetic energy:

kl/ki = 300 m^2/s^2 * m / 612.5 m^2/s^2 * m

kl/ki = 24/49=0.49

7 0
3 years ago
Unpolarized light passes through three polarizing filters. The first one is oriented with a horizontal transmission axis, the se
Xelga [282]

Answer:

10.028%

Explanation:

\theta = Angle between polarizer

The polarized light after passing through first polarizer

I=\frac{I_0}{2}

The polarized light after passing through second polarizer

I_2=\frac{I_0}{2}cos^2\theta\\\Rightarrow I_2=\frac{I_0}{2}cos^231.8\\\Rightarrow I_2=0.36115I_0

The polarized light after passing through third polarizer

I_3=I_2cos^2(90-31.8)\\\Rightarrow I_3=0.36115I_0cos^2(90-31.8)\\\Rightarrow I_3=0.10028I_0

\frac{I_3}{I_0}\times 100=\frac{0.10028I_0}{I_0}\times 100\\ =10.028\ \%

The percent of the light gets through this combination of filters is 10.028%

4 0
3 years ago
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