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2 years ago

A. Change to Percent. Show your work.

2 answers:

6 0

Converting from a decimal to a percentage is done by multiplying the decimal value by 100 and adding To convert a percent to a decimal, we have to remove the percentage sign (%) and divide the number by 100. Dividing by 100 is the same as shifting the decimal

Dafna11 [192]2 years ago

3 0

Answer:

1. 55%

2.7.5 %

3. 09%

4. 25.5 %

5. 1.33%

1 2.0

2. 7.5

3 1.2

4. 12

5. 6.5

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What is the value of 2X^2 +4y if x=-2 y =3

SpyIntel [72]

2X^2 + 4y = 2 * -2^2 + 4 * 3

Your answer is 4.

If this is incorrect, then I am sorry.

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3 years ago

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Mathew’s mom asked him to go to the store for her. To get to the store he walked seven blocks. He caught the bus and rode 13 blo

SVETLANKA909090 [29]

7+13+1.5=21.5

If he did it again the way back, it's 21.5 times 2.

He went a total of 43 blocks.

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3 years ago

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Let P(n) be the statement that n! < nn where n is an integer greater than 1.

Ira Lisetskai [31]

Answer: See the step by step explanation.

Step-by-step explanation:

a) First, Let P(n) be the statement that n! < n^n

where n ≥ 2 is an integer (This is because we want the statement of P(2).

In this case the statement would be (n = 2): P(2) = 2! < 2^2

b) Now to prove this, let's complet the basis step:

We know that 2! = 2 * 1 = 2

and 2^2 = 2 * 2 = 4

Therefore: 2 < 4

c) For this part, we'll say that the inductive hypothesis would be assuming that k! < k^k for some k ≥ 1

d) In this part, the only thing we need to know or prove is to show that P(k+1) is also true, given the inductive hypothesis in part c.

e) To prove that P(k+1) is true, let's solve the inductive hypothesis of k! < k^k:

(k + 1)! = (k + 1)k!

(k + 1)k! < (k + 1)^k < (k + 1)(k + 1)^k

Since k < k+1 we have:

= (k + 1)^k+1

f) Finally, as the base and inductive steps are completed, the inequality is true for any integer for any n ≥ 1. If we had shown P(4)

as our basis step, then the inequality would only be proven for n ≥ 4.

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3 years ago

the area of a rectangular volleyball court is 1800 square feet the courts length is twice it width write a system of equations t

Marianna [84]

Answer:

The dimensions of the rectangular volleyball court are 60 ft x 30 ft

Step-by-step explanation:

Let

x ----> the length of rectangular volleyball court

y ---> the width of the rectangular volleyball court

we know that

The area of the rectangular volleyball court is equal to

$A=xy$

$A=1,800\ ft^2$

$1,800=xy$ ----> equation A

$x=2y$ -----> equation B

substitute equation B in equation A

$1,800=(2y)y$

$1,800=2y^2$

Solve for y

Simplify

$900=y^2$

take square root both sides

$y=30\ ft$

<em>Find the value of x</em>

$x=2y$

substitute the value of y

$x=2(30)=60\ ft$

therefore

The dimensions of the rectangular volleyball court are 60 ft x 30 ft

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3 years ago

Find 92% of 400 cars

mario62 [17]

Answer:

368

Step-by-step explanation:

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3 years ago

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