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2 years ago

A. Change to Percent. Show your work.

2 answers:

6 0

Converting from a decimal to a percentage is done by multiplying the decimal value by 100 and adding To convert a percent to a decimal, we have to remove the percentage sign (%) and divide the number by 100. Dividing by 100 is the same as shifting the decimal

Dafna11 [192]2 years ago

3 0

Answer:

1. 55%

2.7.5 %

3. 09%

4. 25.5 %

5. 1.33%

1 2.0

2. 7.5

3 1.2

4. 12

5. 6.5

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Check whether the relation R on the set S = {1, 2, 3} is an equivalent

kozerog [31]

Answer:

$R$ isn't an equivalence relation. It is reflexive but neither symmetric nor transitive.

Step-by-step explanation:

Let $S$ denote a set of elements. $S \times S$ would denote the set of all ordered pairs of elements of $S\!$ .

For example, with $S = \lbrace 1,\, 2,\, 3 \rbrace$ , $(3,\, 2)$ and $(2,\, 3)$ are both members of $S \times S$ . However, $(3,\, 2) \ne (2,\, 3)$ because the pairs are ordered.

A relation $R$ on $S\!$ is a subset of $S \times S$ . For any two elements $a,\, b \in S$ , $a \sim b$ if and only if the ordered pair $(a,\, b)$ is in $R\!$ .

A relation $R$ on set $S$ is an equivalence relation if it satisfies the following:

Reflexivity: for any $a \in S$ , the relation $R$ needs to ensure that $a \sim a$ (that is: $(a,\, a) \in R$ .)

Symmetry: for any $a,\, b \in S$ , $a \sim b$ if and only if $b \sim a$ . In other words, either both $(a,\, b)$ and $(b,\, a)$ are in $R$ , or neither is in $R\!$ .

Transitivity: for any $a,\, b,\, c \in S$ , if $a \sim b$ and $b \sim c$ , then $a \sim c$ . In other words, if $(a,\, b)$ and $(b,\, c)$ are both in $R$ , then $(a,\, c)$ also needs to be in $R\!$ .

The relation $R$ (on $S = \lbrace 1,\, 2,\, 3 \rbrace$ ) in this question is indeed reflexive. $(1,\, 1)$ , $(2,\, 2)$ , and $(3,\, 3)$ (one pair for each element of $S$ ) are all elements of $R\!$ .

$R$ isn't symmetric. $(2,\, 3) \in R$ but $(3,\, 2) \not \in R$ (the pairs in $\! R$ are all ordered.) In other words, $3$ isn't equivalent to $2$ under $R\!$ even though $2 \sim 3$ .

Neither is $R$ transitive. $(3,\, 1) \in R$ and $(1,\, 2) \in R$ . However, $(3,\, 2) \not \in R$ . In other words, under relation $R\!$ , $3 \sim 1$ and $1 \sim 2$ does not imply $3 \sim 2$ .

3 0

3 years ago

The quotient of 5 less than a number and 6 is -4

Dovator [93]

-1 is the answer or your answer is gonna be false

7 0

3 years ago

Read 2 more answers

while swimming a 2km race, Adam changes from breaststroke to butterfly every 200m. How many times does he switch strokes during

aleksley [76]

in the first half he would have swam 1 km. there are 1000m in a km so 1000/200=5 so he swam the first 200 fly, then a 200 breast, then a 200 fly again, then another 200 breast the finish the first 1 km with a 200 fly. so we switched strokes 4 times.

PS i wouldn't recommend doing a 2 km swim fly and breast

8 0

4 years ago

Read 2 more answers

Can someone be honest and tell me if it’s correct bc I’m not sure someone please help me

patriot [66]

Yes it is........
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5 0

3 years ago

15 over 1000 wrote in scientific notation

Katena32 [7]

Answer:

1.5*10^-2

Step-by-step explanation:

You mean 15/1000 written in scientific notation?

In this case, it would be- 1.5*10^-2.

3 0

3 years ago