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GREYUIT [131]
4 years ago
5

What is the intensity in W/m2 of a laser beam used to burn away cancerous tissue that, when 85.0% absorbed, puts 470 J of energy

into a circular spot 2.60 mm in diameter in 4.00 s?
Physics
1 answer:
Advocard [28]4 years ago
8 0

Answer:

26036485.6433 W/m²

Explanation:

E= Energy = 470 J

t = Time = 4 seconds

d = Diameter = 2.6 mm

Power is given by

P=\dfrac{E}{t}

Intensity is given by

I=\dfrac{P}{\pi r^2}\\\Rightarrow 0.85I=\dfrac{E}{t\dfrac{\pi}{4} d^2}\\\Rightarrow I=\dfrac{470}{0.85\times 4\times \dfrac{\pi}{4}\times (2.6\times 10^{-3})^2}\\\Rightarrow I=26036485.6433\ W/m^2

The intensity of the laser beam is 26036485.6433 W/m²

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Based on its chemical makeup, where do you think amazonite is found? Please help me!
dezoksy [38]
It can be found in the U.S. and other parts around the world! It doesn't come from the Amazon River, but it's been found in Brazil before. Also, Amazonite is a green variety of "Microline Feldspar".
5 0
3 years ago
PLZZZZ HELPPPPPP MEEEEEE!!!!!! ASAP!!! ILL GIVE 20 POINTS AND BRAINLIEST!!!
Snowcat [4.5K]

Answer:

the answers the correct one is C

Explanation:

In radioactive decay processes, a very important concept is the half-life time, which is the time it takes for the parent nuclei to decompose into child nuclei.

expressed this mathematically is

              N = N₀ e^{- \lambda t}

for the average life time

              N₀ / 2 = N₀  e^{- \lambda T_{1/2}

               T =\frac{ln 2x}{ \lambda}

Analyzing this expression, the nuclei that decay are the so-called parents and the new nuclei called children appear.

when checking the answers the correct one is C

3 0
3 years ago
The 10-kg block is held at rest on the smooth inclined plane by the stop block at A. If the 10-g bullet is traveling at 300 m/s
Nadusha1986 [10]

Answer:

d=6.874mm

Explanation:

Linear momentum of the block is conserved in the x\prime direction since the impulsive force due to impact cancels each other internally.

m_bv_b_x=(m_b+m_B)v_x\\(0.01)(300cos 30\textdegree)=(10+0.01)v\\\therefore v=0.259548m/s

Using the conservation of energy to the block system considering the initial position:

T_1+V_1=T_2+V_2\\\\0+0.5(m_b+m_B)v^2=0+(m_b+m_B)gh\\0.5(10+0.01)(0.259548)^2=(0.01+10)(9.8)\\h=0.003437m\\\therefore h=3.437mm

Applying Sine rule:

d=\frac{h}{Sin 30\textdegree}\\d=6.874mm

Hence, the distance the block will slide up is 6.874mm

5 0
3 years ago
A 20.00 kg lead sphere is hanging from a hook by a thin, massless wire 2.80 m long and is free to swing in a complete circle. Tr
Tema [17]

The minimum initial speed of the dart so that the combination makes a complete circular loop after the collision is 58.5 m/s.

<h3>Minimum speed for the object not fall out of the circle</h3>

The minimum speed if given by tension in the wire;

T + mg = ma

T + mg = m(v²)/R

tension must be zero for the object not fall

0 + mg = mv²/R

v = √(Rg)

<h3>Final speed of the two mass after collision</h3>

Use the principle of conservation of energy

K.Ef  = K.Ei + P.E

¹/₂mvf² = ¹/₂mv² + mg(2R)

¹/₂vf² = ¹/₂v² + g(2R)

¹/₂vf² = ¹/₂(Rg) + g(2R)

vf² = Rg + 4Rg

vf² = 5Rg

vf = √(5Rg)

vf = √(5 x 2.8 x 9.8)

vf = 11.7 m/s

<h3>Initial speed of the dart</h3>

Apply principle of conservation of linear momentum for inelastic collision;

5v = vf(20 + 5)

5v = 11.7(25)

5v = 292.5

v = 58.5 m/s

Learn  more about linear momentum here: brainly.com/question/7538238

#SPJ1

3 0
2 years ago
What is the mass of an object whose momentum is 35kg-m/s ..when its velocity is 7m/s​
MAXImum [283]

Answer:

5kg

Explanation:

p = mv

m = p/v

m = 35/7

m = 5kg

4 0
3 years ago
Read 2 more answers
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