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ella [17]
2 years ago
13

Find the mole fraction of Methanol CH3OH and water in a solution prepared by dissolving 4.5 g of alcohol in 40 g of H2O.

Chemistry
1 answer:
polet [3.4K]2 years ago
6 0
Calculations a technician performs for the CSP should be located on the O a) standard operating procedure (SOP). b) master formulation record (MFR). O) compounding record (CR). d) quality assurance
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Tatiana [17]

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balances and scales, measurement transducers, vibrating tube sensors, Newtonian mass measurement devices and the use of gravitational interaction between objects.

Explanation:

4 0
3 years ago
Nvm i got it lol how do i delete
Lady_Fox [76]

Answer:

delete what?

Explanation:

3 0
3 years ago
Why are valence electrons important
koban [17]

Explanation:

The electrons in the outermost shell of an atom are the valence electrons. These electrons are the most loosely held in an atom.

The energy required to remove these electrons are not as great as those of the inner shell electrons.

  • Atoms of some elements show no tendency to combine with other  atoms because they have completely filled outer energy levels.
  • Their outermost shell, valence shell and the electron numbers are complete for them. These are the noble gases.
  • other atoms share or exchange their valence electrons in order to have a stable configuration.
  • The valence electrons are involve in inter-atomic bond formation and interactions
  • Also the distribution of these electrons determines inter-molecular interactions between molecules.

Learn more:

valence electrons in metalloids brainly.com/question/3023499

#learnwithBrainly

4 0
3 years ago
Read 2 more answers
Whoever answers correctly I’ll give you a Brainly
Andre45 [30]

Answer:

answer is B

Explanation:

3 0
2 years ago
Read 2 more answers
Normally the capital ÎGo° for a reaction would be determined at standard temperature with each reactant at a concentration of 1
Arte-miy333 [17]

Answer:

d.-379 cal/mol

Explanation:

ΔG = ΔG⁰ + RT ln K

for equilibrium ΔG = 0

ΔG⁰ + RT ln K =0

ΔG⁰   =  -  RT ln K

PG ⇒ PEP

K = [ PEP ] / [ PG ]

= .68 / .32

= 2.125

ΔG⁰   =   - 1.987 x 273 x  ln 2.125

= - 409 Cal / mole

Option d is the nearest answer .

8 0
3 years ago
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