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AleksandrR [38]
3 years ago
14

In one to two sentences, explain a similarity and a difference between the particles in liquid water at 100ºC and the particles

in steam at 100ºC. PLEASSSSSSSSSSSSSSSE HELPPPPPPPPPPPPPPP ASAPPPPPPPPPP........................
Chemistry
1 answer:
kvasek [131]3 years ago
3 0

WOW! I have the same question! Again lol.

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How many molecules of CH4 are in 24.1 g of this compound?
jok3333 [9.3K]

<u>1) find molar mass of CH₄</u>

=12.01+4(1.01)\\\\=16.05\ g/mol

<u>2) determine moles of CH₄</u>

=24.1g\ CH_{4}\ x\ \frac{1\ mol\ CH_{4}}{16.05g\ CH_{4}}\\\\=1.501557632\ mol\ CH_{4}

<u>3) multiply by avogadro's number</u>

=1.501557632\ mol\ CH_{4}\ x\ \frac{6.022\ x\ 10^{23}\ molecules\ CH_{4}}{1\ mol\ CH_{4}} \\\\=9.04238006\ x\ 10^{23}\\\\=9.04\ x\ 10^{23}\ molecules\ CH_{4}

7 0
2 years ago
Density is an example of a​
Readme [11.4K]
A rock is obviously more dense than a crumpled piece of paper of the same size. A styrofoam cup is less dense than a ceramic cup.


hope this helps if it do mark me as brainlest thank you !!
7 0
3 years ago
Consider an atom of oxygen in which the nucleus contains 8 protons and 8 neutrons. If it is doubly ionized, what is the charge o
inn [45]

Answer:

10 electrons will be present in an O2-

Explanation:

The atomic nucleus of oxygen contains 8protons and 8 neutron. It ionizes by gaining two more electrons making the total number of electrons in a doubly ionized oxygen to be 10 electrons.

7 0
3 years ago
what is the empirical formula of vanadium 1 oxide given that 20.38 grams of vandium combines with oxygen to form 23.58 grams of
Alex

Answer:

The empirical formula is V₂O

Empirical formula of a compound is the formula that shows the simplest whole number ratio of the atoms of elements in a given compound. Empirical formula is normally calculated when the mass of each element in a compound is known or the percentage composition by mass of each element in a compound is known.

Step by Step Explanation:

Step 1: Percentage composition of each element

Percentage composition=(mass of an element/ mass of the compound)100%

Mass of Vanadium = 20.38 g

Mass of the compound = 23.58 g

% composition of Vanadium = (20.38 g/23.58 g) 100%

                                                 = 86.43 %

Mass of Oxygen = 23.58 g -20.38 g

                           = 3.2 g

% composition of oxygen = (3.2/g/23.58 g) 100%

                                          =  13.57%

Step 2: Find the number of atoms of each element in the compound

Number of atoms  = percentage composition/ atomic mass

Atomic mass of Vanadium = 50.94 g/mol

Number of atoms of V = 86.43 /50.94

                                  = 1.6967

Atomic mass of oxygen = 16 g/mol

Number of atoms of O = 13.57/16

                                      = 0.8481

Step 3:  Find the simplest ratio of atoms

Vanadium : Oxygen

            1.6967 : 0.8481

= 1.6967/0.8481 : 0.8481/0.8481

= 2: 1

Whole number ratio = 2 : 1

Therefore; the empirical formula is V₂O

8 0
3 years ago
Read 2 more answers
What would the formula be for this model above?
Daniel [21]

Answer:

CH4

Explanation:

A= CH4

8 0
3 years ago
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