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2 years ago

Match the term with the definition.

Chemistry

2 answers:

statuscvo [17]2 years ago

6 0

freezing is a phase change from liquid to solid

evaporation is a phase change from liquid to gas

sublimation is a phase change from solid to gas

condensation is a phase change from gas to liquid

MASHA ALLAH

elena-s [515]2 years ago

6 0

Explanation:

Condensation is defined as the process in which vapor or gaseous state of a substance changes into liquid state.

Evaporation is defined as the process in which liquid state of a substance changes into gaseous state.

Sublimation is defined as the process in which a solid substance directly changes into gaseous state without undergoing liquid state.

Freezing is defined as the process in which liquid state of a substance changes into solid state.

Therefore, the given terms are matched as follows.

Condensation : D) A phase change from a gas to a liquid

Evaporation : B) A phase change from a liquid to a gas

Sublimation : C) A phase change from a solid to a gas

Freezing : A) A phase change from a liquid to a solid

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Inner thigh, eyes, brain

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3 years ago

An ambulance took 2 hours to cover a distance of 10 kilometers. Find its speed.

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2 years ago

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If 21.00 mL of a 0.68 M solution of C6H5NH2 required 6.60 mL of the strong acid to completely neutralize the solution, what was

Andru [333]

Answer:

pH = 2.46

Explanation:

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In this case, since this neutralization reaction may be assumed to occur in a 1:1 mole ratio between the base and the strong acid, it is possible to write the following moles and volume-concentrations relationship for the equivalence point:

$n_{acid}=n_{base}=n_{salt}$

Whereas the moles of the salt are computed as shown below:

$n_{salt}=0.021L*0.68mol/L=0.01428mol$

So we can divide those moles by the total volume (0.021L+0.0066L=0.0276L) to obtain the concentration of the final salt:

$[salt]=0.01428mol/0.0276L=0.517M$

Now, we need to keep in mind that this is an acidic salt since the base is weak and the acid strong, so the determinant ionization is:

$C_6H_5NH_3^++H_2O\rightleftharpoons C_6H_5NH_2+H_3O^+$

Whose equilibrium expression is:

$Ka=\frac{[C_6H_5NH_2][H_3O^+]}{C_6H_5NH_3^+}$

Now, since the Kb of C6H5NH2 is 4.3 x 10^-10, its Ka is 2.326x10^-5 (Kw/Kb), we can also write:

$2.326x10^{-5}=\frac{x^2}{0.517M}$

Whereas x is:

$x=\sqrt{0.517*2.326x10^{-5}}\\\\x=3.47x10^-3$

Which also equals the concentration of hydrogen ions; therefore, the pH at the equivalence point is:

$pH=-log(3.47x10^{-3})\\\\pH=2.46$

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2 years ago

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Romashka-Z-Leto [24]

Answer:

New experimental methods

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However, experimental methods are limited to the caliber of equipments available at the time in which a theory is formulated. With advancing years, more technological sophistication leads to the invention of new instruments and ultimately, the development of new experimental methods.

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3 years ago

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Show the equation how many grams of Mg(OH)2 would be produced from 4 mol KOH?

Sindrei [870]

Mole ratio:

MgCl₂ + 2 KOH = Mg(OH)₂ + 2 KCl

2 moles KOH ---------------- 1 mole Mg(OH)₂
4 moles KOH ------------------- moles Mg(OH)₂

moles Mg(OH)₂ = 4 x 1 / 2

= 2 moles of   Mg(OH)₂

molar mass Mg(OH)₂ = 58g/mol

mass of   Mg(OH)₂ = n x mm

mass of  Mg(OH)₂ = 58 x 2

= 116 g of <span> Mg(OH)₂</span>

hope this helps!

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2 years ago