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3 years ago

Match the term with the definition.

Chemistry

2 answers:

statuscvo [17]3 years ago

6 0

freezing is a phase change from liquid to solid

evaporation is a phase change from liquid to gas

sublimation is a phase change from solid to gas

condensation is a phase change from gas to liquid

MASHA ALLAH

elena-s [515]3 years ago

6 0

Explanation:

Condensation is defined as the process in which vapor or gaseous state of a substance changes into liquid state.

Evaporation is defined as the process in which liquid state of a substance changes into gaseous state.

Sublimation is defined as the process in which a solid substance directly changes into gaseous state without undergoing liquid state.

Freezing is defined as the process in which liquid state of a substance changes into solid state.

Therefore, the given terms are matched as follows.

Condensation : D) A phase change from a gas to a liquid

Evaporation : B) A phase change from a liquid to a gas

Sublimation : C) A phase change from a solid to a gas

Freezing : A) A phase change from a liquid to a solid

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Balance the equations.<br> Zn+ HCl →<br> ZnCl2 +

motikmotik

Answer:

Zn + 2HCl → ZnCl2 + H2

Explanation:

Zn + HCl → ZnCl2 +

The complete equation is given below:

Zn+ HCl → ZnCl2 + H2

Now we can balance the equation by doing the following:

There are 2 atoms of Cl and 2 atoms of H on the left. This can be balanced by putting 2 in front of HCl as shown below:

Zn + 2HCl → ZnCl2 + H2

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3 years ago

A 0.8715 g sample of sorbic acid, a compound first obtained from the berries of a certain ash tree, is burned completely in oxyg

aivan3 [116]

<h3><u>Answer</u>;</h3>

C3H4O

<h3><u>Explanation;</u></h3>

Empirical formula is the simplest formula of a compound;

Molar mass CO2 = 44.01

Mass of CO2 produced = 2.053 g

Mass of carbon in original sample = 12.01/44.01 × 2.053

= 0.5603g

Molar mass H2O = 18

Mass of H in original sample = 2/18 ×0.5601

= 0.0622 g

Thus; original sample contained 0.5603g C and 0.0622g H. The balance of the sample was O

Mass of O = 0.8715 - (0.5603 + 0.0622) = 0.249g

The mole ratio of C:H:O will be;

Moles C = 0.5603/12 = 0.0467

Moles H = 0.0622

Moles O = 0.249/16 = 0.01556

C:H:O = 0.0467:0.0622:0.01556

Divide through by 0.01556:

C:H:O = 3:4:1

Empirical formula is thus C3H4O

8 0

4 years ago

Read 2 more answers

What is The element in group 4 and period 3.

Rina8888 [55]

Explanation:

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3 years ago

Which states of matter only appear in the hydrosphere

Oliga [24]

I would say the answer is liquids

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3 years ago

A 10.0 mL sample of 0.75 M CH3CH2COOH(aq) is titrated with 0.30 M NaOH(aq) (adding NaOH to CH3CH2COOH). Determine which region o

Llana [10]

Answer:

5.75

Explanation:

Weak acid and strong base,

Make it a two part problem

The first will be Partial neutralization of the weak acid, while the second is the equilibrium and final pH

1.Parameters

HC2H3O2 =10mL x 0.75M = 7.5 mmol

NaOH =22mL x 0.30M = 6.6 mmol

R HC2H3O2 + OH- --> C2H3O2- + H2O

I 7.5 mmol 6.6 mmol 0 mmol ignore

C -6.6 mmol -6.6 mmol +6.6 mmol

E 0.9 mmol 0.0 mmol 6.6 mmol

2.) HC2H3O2 --> H+ + C2H3O2-

Initial concentrations

[HC2H3O2]: 0.9 mmol / 32mL = 0.0281M

[H+]:

[C2H3O2-]: 6.6 mmol x 32mL = 0.206M

Concentrations at equilibrium

[HC2H3O2]: 0.0281M - x

[H+]: [C2H3O2-]: 0.206M + x

If x is small and can be ignored except [H+]

Substitute and solve

1.3 x 10-5 = (x)(0.206)

(0.0281)

X= 1.77 x 10-6M => pH = 5.75

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3 years ago