Answer:
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Explanation:
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Answer:
NiS insoluble
Mg₃(PO₄)₂ insoluble
Li₂CO₃ soluble
NH₄Cl soluble
C₁₂H₂₂O₁₁ molecules
Explanation:
<em>Predict whether the following compounds are soluble or insoluble in water.</em>
Based on the solubility rules we can say:
- NiS: Sulfides of transition metals are highly insoluble.
- Mg₃(PO₄)₂: All phosphates (except those with metals of Group 1) are insoluble so Mg₃(PO₄)₂ is insoluble.
- Li₂CO₃: all salts of metals of Group 1 are soluble so Li₂CO₃ is soluble.
- NH₄Cl: all salts of ammonium are soluble so NH₄Cl is soluble.
<em>Which of the following best describes the solute in an aqueous solution of sucrose or C₁₂H₂₂O₁₁(aq)?</em>
Sucrose is a molecular compound in which atoms are linked through covalent bonds. Thus, it does not ionize in water (is a non-electrolyte) and when it dissolves it exists as C₁₂H₂₂O₁₁ molecules.
Explanation:
In a magnetic field, the radius of the charged particle is as follows.
r = 
where, m = mass, v = velocity
q = charge, B = magnetic field
Therefore, q will be calculated as follows.
q = 
= 
= 
= 
= +2e
Thus, we can conclude that the charge of the ionized atom is +2e.
