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<span>We have the number 81 as the largest perfect square in the range of the statement.
Since we have it as the largest square, then its largest possible modulus of "x" will be when </span>
<span>, that is, when </span>
<span>.
Since it is the largest possible module, the rightmost number of the "0" in the line of integers, with the largest number being x = 9 and the leftmost number of the "0" in the line of integers, , Will be </span>
<span>
Therefore, the difference requested in the statement is:
</span>
Since we have it as the largest square, then its largest possible modulus of "x" will be when </span>
Since it is the largest possible module, the rightmost number of the "0" in the line of integers, with the largest number being x = 9 and the leftmost number of the "0" in the line of integers, , Will be </span>
Therefore, the difference requested in the statement is:
</span>
Answer:
The mass of 1000 atoms of gold is, in grams, of
Step-by-step explanation:
This question is solved by proportions, using a rule of three.
We have that:
One atom of gold has a mass, in grams, of . What is the mass of 1000 atoms of gold?
1000 atoms is . So
1 atom - grams
atoms - x
Applying cross multiplication:
The mass of 1000 atoms of gold is, in grams, of