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tatyana61 [14]
2 years ago
9

Is ABC~ DEF? If so, identify the similarity postulate or theorem that applies.

Mathematics
1 answer:
yarga [219]2 years ago
8 0

Answer:

a

Step-by-step explanation:

i hope it helps

*correct me if im wrong

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How do I know an equation is downhill
mr_godi [17]

Answer:

The graph of a linear equation can either run uphill or downhill. The slope is positive when the line is uphill, while the downhill line represents a negative slope. To find the slope, find two coordinates along the line.

8 0
3 years ago
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What is Discount Comics is running a special: 20 comics for $5.00. Seth purchases 30 comics for $7.50. What is the sale price pe
Shalnov [3]
Since we are finding the unit rate of the cost per comic, we will need to divide $5 by 20 comics which you will get 0.25 cents and divide $7.50 by 30 comics which you will also get 0.25 cents.Therefore, the unit rate and constant of proportionality is 0.25 cents.
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3 years ago
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If <br> B is the midpoint of AC, AB=x+6 and AC=5x-6, then what is BC?
nikklg [1K]

If B is the midpoint of AC, then AB=BC. It is also BC=AC-AB

AB = x + 6

AC = 5x - 6

BC = (5x - 6) - (x + 6)

We can kinda use distributive property, like this:

BC = 5x - 6 -x - 6

Combine like terms:

BC = 4x - 12

To verify, we can add AB and BC to see if their sum is equal to AC.

(x + 6) + (4x - 12) = 5x - 6

If we are correct, this equation will be true.

x + 6 + 4x - 12 = 5x - 6

Combine like terms:

6 + 5x - 12 = 5x - 6

5x - 6 = 5x - 6

It's correct!

BC = 4x - 12. Final Answer.

Let me know if you have any questions about this! :)

7 0
3 years ago
Can someone help me plz??
Brut [27]

Answer:

96π

Step-by-step explanation:

v =  \frac{1}{3}  {r}^{2} h\pi

V=96π

5 0
3 years ago
What is the product?
ZanzabumX [31]

Answer:

The product is:

\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]

Step-by-step explanation:

For this problem you need to multiply the first row only for the two first column of the others matrix and get the desired result:

\left[\begin{array}{ccc}1&3&1\\-2&1&0\end{array}\right] \times \left[\begin{array}{cc}2&-2\\3&5\\4&1\end{array}\right]

1 \times 2 + 3 \times 3 + 1 \times -2 = 15

So the value of the element in the position a_{11} is 15

1 \times -2 + 3 \times 5 + 1 \times 1 = 14

So the value of the element in the position a_{12} is 14

Then with these two values you can determinate the result matrix.

\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]

3 0
3 years ago
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