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nikitadnepr [17]
2 years ago
11

Tasks on a checklist should be written in as general terms as possible so that developers and artists have enough creative freed

om to create interesting products.
O true
O false
Computers and Technology
2 answers:
vladimir2022 [97]2 years ago
8 0
True is the answer of the queen
GrogVix [38]2 years ago
7 0

Answer:  True

Explanation: Developers who design always take on idea that was created and add to it. Creating a piece of artwork/ Item.

You might be interested in
Given non-negative integers x and n, x taken to the nth power can be defined as: x to the 0th power is 1 x to the nth power can
saveliy_v [14]

Answer:

The power function can be written as a recursive function (using Java) as follows:

  1. static int power(int x, int n)
  2. {
  3.        if(n == 0){
  4.            return 1;
  5.        }
  6.        else {
  7.            return power(x, n-1 ) * x;
  8.        }
  9. }

Explanation:

A recursive function is a function that call itself during run time.

Based on the question, we know x to the 0th power is 1. Hence, we can just create a condition if n = 0, return 1 (Line 3 - 5).

Next, we  implement the logic "x to the nth power can be obtained by multiplying x to the n-1'th power with x " from the question with the code:  return power(x, n-1 ) * x in the else block. (Line 6 -8)

In Line 7, power() function will call itself recursively by passing x and n-1 as arguments. Please note the value of n will be reduced by one for every round of recursive call. This recursive call will stop when n = 0.

Just imagine if we call the function as follows:

int result =  power(2,  3);

What happen  will be as follows:

  • run Line 7 -> return power(2, 2) * 2    
  • run Line 7 -> return power(2, 1) * 2
  • run Line 7 -> return power(1, 0) * 2
  • run Line 4 -> return 1    (Recursive call stop here)

Next, the return value from the inner most recursive call will be return to the previous call stack:

  • power(1, 0) * 2   ->   1 * 2
  • power(2, 1) * 2   ->   1 * 2 * 2
  • power(2, 2) * 2   ->   1 * 2 * 2 * 2 - > 8 (final output)  
4 0
3 years ago
The destructor automatically executes when the class object goes out of ____.
Tema [17]

Answer:

scope    

Explanation:

Destructor is a member function and it call automatically when the class object goes out of scope.

Out of scope means, the program exit, function end etc.

Destructor name must be same as class name and it has no return type.

syntax:

~class_name() { };

For example:

class xyz{

  xyz(){

        print(constructor);

   }

~xyz(){

        print(destructor);

   }

}

int main(){

    xyz num;

   

}//end program

when the object is create the constructor will called and when the program end destructor will call automatically.

4 0
3 years ago
This question involves the implementation of the PasswordGenerator class, which generates strings containing initial passwords f
liq [111]

The following code will be used for the PasswordGenerator class.

<u>Explanation:</u>

import java.util.Random;

public class PasswordGenerator {

   private static int passwordsGenerated =0;

   private static Random random = new Random();

   private String prefix;

   private int length;

   public PasswordGenerator(int length,String prefix) {

       this.prefix = prefix;

       this.length = length;

   }

   public PasswordGenerator(int length) {

       this.prefix = "A";

       this.length = length;

   }

   public String pwGen(){

       String pwd= this.prefix+".";

       for(int i=1;i<=this.length;i++){

           pwd+=random.nextInt(10);

       }

       passwordsGenerated+=1;

       return pwd;

   }

   public int pwCount(){

       return passwordsGenerated;

   }

   public static void main(String[] args) {

       PasswordGenerator pw1 = new PasswordGenerator(4,"chs");

       System.out.println(pw1.pwCount());

       System.out.println(pw1.pwGen());

       System.out.println(pw1.pwGen());

       System.out.println(pw1.pwCount());

       PasswordGenerator pw2 = new PasswordGenerator(6);

       System.out.println(pw2.pwCount());

       System.out.println(pw2.pwGen());

       System.out.println(pw2.pwCount());

       System.out.println(pw1.pwCount());

   }

}

8 0
2 years ago
Can someone please help me! It’s due Thursday!
Eva8 [605]

Answer:

if the input is zero the out put is 1

Explanation:

because if you think about it if the input was 1 the output would be zero

7 0
2 years ago
Write a c program to count the total number of commented characters and words in a c file taking both types of c file comments (
Tanzania [10]

#include<stdio.h>

#include<stdlib.h>

int comment1(FILE *fp)

{

   char ch;

   int count=0;

   while(fscanf(fp,"%c",&ch)!=EOF)

   {

       if(ch=='\n')

       {

           return count;

       }

       count++;

   }

   return count;

}

int comment2(FILE *fp)

{

   char ch;

   int count=0;

   while(fscanf(fp,"%c",&ch)!=EOF)

   {

       if(ch=='*')

       {

           fscanf(fp,"%c",&ch);

           if(ch=='/')

           {

               return count;

           }

           count++;

       }

       count++;

   }

   return 0;

}

int main()

{

   printf("Enter the file name:");

   char s[1000],ch,ch1;

   scanf("%s",s);

   FILE*fp;

   fp = fopen(s,"r");

   int count=0;

   while(fscanf(fp,"%c",&ch)!=EOF)

   {

       if(ch=='\"')

       {

           while(fscanf(fp,"%c",&ch)!=EOF)

           {

               if(ch=='\"')

               {

                   break;

               }

               if(ch=='\\')

               {

                   fscanf(fp,"%c",&ch);

               }

           }

       }

       else if(ch=='/')

       {

           fscanf(fp,"%c",&ch);

           if(ch=='/')

           {

               count += comment1(fp);

           }

           else if(ch=='*')

           {

               count += comment2(fp);

           }

       }

   }

   printf("%d\n",count);

   return 0;    

}

3 0
3 years ago
Read 2 more answers
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