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2 years ago

What is the volume of this container 1ft 1ft 2ft

Mathematics

2 answers:

Mekhanik [1.2K]2 years ago

8 0

Answer:

Remember length times width times height when finding volume.

In non-terms of pi, the answer would be $2$ $ft^2$

Ahat [919]2 years ago

8 0

Answer:

Volume is 2ft

Step-by-step explanation:

Multiply the length x width once you find the answer for lengthxwidth.

Multiply the answer you got by height

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What is the area of the square given the side length 20.5in

PtichkaEL [24]

Answer: 420.25in^2

Step-by-step explanation:

Area of Square = s^2

20.5^2 = 420.25

7 0

3 years ago

Read 2 more answers

To rent a certain meeting room, a college charges a reservation fee of $37 and an additional fee of $6.70 per hour. the chemistr

mojhsa [17]

37 + 6.70t < 90.60
6.70t < 90.60 - 37
6.70t < 53.6
t < 53.6 / 6.70
t < 8 <=== they could rent the meeting room for less then 8 hrs

3 0

3 years ago

In the Journal of Shell and Spatial Structures (December 1963), environmental researcher Vivek Ajmani studied the performance of

igomit [66]

Answer:

The standard deviation of the load distribution is of 5102.041 pounds.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 20000$

Also, the probability that the load is between 10,000 and 30,000 pounds is 0.95.

10,000 pounds and 30,000 pounds are equidistant from the mean. Due to this, and the probability of 0.95 of having a value in this range, 10000 is the (100-95)/2 = 2.5th percentile and 30000 is the (100+95)/2 = 97.5th percentile. Applying one of them, we find the standard deviation.

30,000 is the 97.5th percentile:

This means that when X = 30000, Z has a pvalue of 0.975. So when X = 30000, Z = 1.96. Then

$Z = \frac{X - \mu}{\sigma}$

$1.96 = \frac{30000 - 20000}{\sigma}$

$1.96\sigma = 10000$

$\sigma = \frac{10000}{1.96}$

$\sigma = 5102.041$

The standard deviation of the load distribution is of 5102.041 pounds.

8 0

3 years ago

Which of the following are point slope equations of the line going through (-3, -5) and (2, 4). Help is appreciated!

ki77a [65]

Answer:

A and F

Step-by-step explanation:

first figure out the slope.

4-(-5)/2-(-3)= 9/5

slope: 9/5

y-y1=m(x-x1)

you substitute either coordinate for the second variables. we automatically take out any slopes that have a negative because the slope is positive.

C, D, E all have negative slopes so it is wrong.

B does not work because a negative times a negative is a positive. the equation shows it to be negative so it is wrong.

A & F fit the solution.

8 0

3 years ago

Find the value or measure. Assume all lines that appear to be tangent are tangent. X=

aev [14]

According to the secant-tangent theorem, we have the following expression:

$(x+3)^2=10.8(19.2+10.8)$

Now, we solve for <em>x</em>.

$\begin{gathered} x^2+6x+9=10.8(30) \\ x^2+6x+9=324 \\ x^2+6x+9-324=0 \\ x^2+6x-315=0 \end{gathered}$

Then, we use the quadratic formula:

$x_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Where a = 1, b = 6, and c = -315.

$\begin{gathered} x_{1,2}=\frac{-6\pm\sqrt[]{6^2-4\cdot1\cdot(-315)}}{2\cdot1} \\ x_{1,2}=\frac{-6\pm\sqrt[]{36+1260}}{2}=\frac{-6\pm\sqrt[]{1296}}{2} \\ x_{1,2}=\frac{-6\pm36}{2} \\ x_1=\frac{-6+36}{2}=\frac{30}{2}=15 \\ x_2=\frac{-6-36}{2}=\frac{-42}{2}=-21 \end{gathered}$ <h2>Hence, the answer is 15 because lengths can't be negative.</h2>

7 0

1 year ago