Please Help Me Answer Numbers 7, 9, 10, and 11!

A single alkyl bromide reactant theoretically yields either of the given products, depending on the reaction conditions. Draw th

Ierofanga [76]

Answer:

$H_{3}C$ -- $H_{3}C$ -- $CH_{3}$ --Br-- $CH_{3}$

Explanation:

The steps involved in predicting the structure of the alkyl bromide compound are outlined below.

1) An examination of the product shows that the product could only be formed by a substitution reaction.

2) The structure of the alkyl bromide compound can be then predicted by replacing the methoxide group in the product after the substitution of bromine atom. This is because the methoxide ion acts as a strong nucleophile.

Therefore, by consideration the reaction mechanisms of reactions 1 and 2, it can be predicted that the structure of the alkyl bromide compound is $H_{3}C$ -- $H_{3}C$ -- $CH_{3}$ --Br-- $CH_{3}$ . A pictorial diagram of the alkyl bromide compound is also attached.

8 0

3 years ago

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What property of an element does the group number identify in a numbering system that uses "A" and "B"?

VMariaS [17]

The number of valence electrons. :) have a good day

8 0

3 years ago

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What is carbon in the lithosphere initially a part of before part of the burning of fossil fuel?

dedylja [7]

Carbon in the lithosphere is held in soil in the form of both organic and inorganic carbon which often as calcium carbonate. Carbon can leave the soil through soil respiration – which releases CO2, or by erosion – which can carry it into rivers or the ocean, where it then enters the hydrosphere.

7 0

2 years ago

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Ima 5% glucose solution, how many grams of glucose would be present per 100mL

Sedaia [141]

Percentage Weight-in-volume is defined as the number of grams of a solute in a 100 ml (milliliters) solution.

Percentage Weight-in-volume can tell us about the degree of concentration of a given solution.

The solute can be crystalline or non-crystalline in nature.

The number of grams of glucose present in a 5% glucose solution is 5 grams.

This question is based on a Percentage Weight-in-volume. The formula states that:

a% of a glucose solution = a grams of glucose in a 100 mL solution

Hence, 5% glucose solution = 5 grams of glucose / 100 mL solution

Therefore, the number of grams of glucose present in a 5% glucose solution is 5 grams.

To learn more, visit the link below:

brainly.com/question/8482854

6 0

1 year ago

A 0.56 M solution of AlCl₃ is determined to have a concentration of particles of 1.79 M. What is the van't Hoff factor for AlCl₃

Crank

Answer:

Van't Hoff factor for AlCl₃ = 3 (Approx)

Explanation:

Given:

Number of observed particular = 1.79 M

Number of theoretical particular = 0.56 M

Find:

Van't Hoff factor for AlCl₃

Computation:

Van't Hoff factor for AlCl₃ = Number of observed particular / Number of theoretical particular

Van't Hoff factor for AlCl₃ = 1.79 M / 0.56 M

Van't Hoff factor for AlCl₃ = 3.19

Van't Hoff factor for AlCl₃ = 3 (Approx)

3 0

2 years ago