If a measurement is 4.2 cm and its possible error is 0.04 cm, the relative error is?
1 answer:
Given the value of possible error, the relative error of the measurement is 0.0095.
Given the data in the question;
- Measurement taken;
- Absolute or possible erorr;
- Relative error;
Relative error is simply the ratio of the absolute or possible error of a measurement to the measurement its self.
Relative error is expressed as;
Where e is the absolute or possible error and m is the measurement being taken.
To determine the relative error, we substitute our given values into the expression above.
%
Therefore, given the possible error, the relative error of the measurement is 0.0095.
Learn more about relative error: brainly.com/question/17016021
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The final velocity of the bullet+block is 0.799 m/s
Explanation:
We can solve this problem by applying the principle of conservation of momentum: in fact, the total momentum of the bullet-block system must be conserved before and after the collision.
Mathematically, we can write:
where
m = 0.001 kg is the mass of the bullet
u = 800 m/s is the initial velocity of the bullet
M = 1 kg is the mass of the block
U = 0 is the initial velocity of the block (initially at rest)
v is the final combined velocity of the bullet and the block
Solving the equation for v, we find the final velocity:
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