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2 years ago

If a measurement is 4.2 cm and its possible error is 0.04 cm, the relative error is?

Physics

1 answer:

galben [10]2 years ago

3 0

Given the value of possible error, the relative error of the measurement is 0.0095.

Given the data in the question;

Measurement taken; $m = 4.2cm$

Absolute or possible erorr; $e = 0.04m$

Relative error; $RE = \ ?$

<h3>Relative Error</h3>

Relative error is simply the ratio of the absolute or possible error of a measurement to the measurement its self.

Relative error is expressed as;

$RE = \frac{e}{m}$

Where e is the absolute or possible error and m is the measurement being taken.

To determine the relative error, we substitute our given values into the expression above.

$RE = \frac{0.04cm}{4.2cm} \\\\RE = 0.0095$ %

Therefore, given the possible error, the relative error of the measurement is 0.0095.

Learn more about relative error: brainly.com/question/17016021

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If a measurement is 4.2 cm and its possible error is 0.04 cm, the relative error is?​

If a measurement is 4.2 cm and its possible error is 0.04 cm, the relative error is?