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tresset_1 [31]
2 years ago
15

If a measurement is 4.2 cm and its possible error is 0.04 cm, the relative error is?​

Physics
1 answer:
galben [10]2 years ago
3 0

Given the value of possible error, the relative error of the measurement is 0.0095.

Given the data in the question;

  • Measurement taken; m = 4.2cm
  • Absolute or possible erorr; e = 0.04m
  • Relative error; RE = \ ?

<h3>Relative Error</h3>

Relative error is simply the ratio of the absolute or possible error of a measurement to the measurement its self.

Relative error is expressed as;

RE = \frac{e}{m}

Where e is the absolute or possible error and m is the measurement being taken.

To determine the relative error, we substitute our given values into the expression above.

RE = \frac{0.04cm}{4.2cm} \\\\RE = 0.0095%

Therefore, given the possible error, the relative error of the measurement is 0.0095.

Learn more about relative error: brainly.com/question/17016021

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Tresset [83]

This question is an illustration of the distance postulate.

<h3>What is distance postulate ?</h3>

The distance between any two different points equates to a single positive real integer, according to the postulate of distance.

The full text is: The distance is a positive unique integer between every pair of different locations.

Consider two separate points A and B as an example.

The distance between A and B is the integer that represents the size of A and B.

The positive number (i.e. the distance) between A and B would be:

d= B-A

d = 6 - 1

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3 0
2 years ago
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ch4aika [34]

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<h3>Which 4 moons are known?</h3>

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<h3>Can Earth have Two moons?</h3>

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1 year ago
True or false velocity is the slope of the acceleration versus time graph
Elena-2011 [213]

I'm pretty sure it is true. (78% sure)

5 0
3 years ago
Read 2 more answers
.2, A car starting from rest has an acceleration of
riadik2000 [5.3K]

Answer: 2.5 m/s and 6.25 m

Explanation:

u = 0

a = 0.5 m/s²

t = 5 s

v = u + at

=  0 + 0.5 × 5

= <u>2.5 m/s</u>

s = ut + 1/2 at²

= 1/2 × 2.5 × 5

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7 0
3 years ago
If a soap bubble is 115 nm thick, what wavelength is most strongly reflected at the center of the outer surface when illuminated
sp2606 [1]

Answer:

611.8 nm

Explanation:

n_{oil} = Index of refraction of soap bubble  = 1.33

t = thickness of the soap bubble = 115 nm = 115 x 10⁻⁹ m

\lambda = wavelength of light = ?

m = order = 0

For reflection , the necessary condition is

2 n_{oil} t = (m + 0.5) \lambda

2 (1.33)(115\times 10^{-9})= (0 + 0.5) \lambda

\lambda = 6.118\times 10^{-7}

\lambda = 611.8 nm

7 0
3 years ago
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