Answer:
The length of each side of the square is (2a-5)units
Step-by-step explanation:
4a^2 - 20a +25
= (2a)^2 - 20a + (-5)^2
=(2a - 5)^2
Since the length of a square given a l produces an area l^2 then the length of the side l is the square root of the area l^2
length of side is therefore square root of (2a -5)^2 which is (2a-5)
The area of a rectangle whose one side is x and the other is y is xy, the product of x and y.
(9a^2 - 16b^2)
= (3a)^2 - (4b)^2 this is the difference of two squares, the factors are therefore
= (3a + 4b) * (3a - 4b)
The dimensions of the rectangle are:
one pair of opposite sides are 3a + 4b
and the other pair of opposite side perpendicular to the first pair is 3a - 4b
Answer:
Step-by-step explanation:
Let d be the number of days.
We have been that each day Katie finds 12 more seashells on beach, so after collecting shells for d days Katie will have 12d shells.
We are also told that Katie already has 34 seashells in her collection, so total number of shells in Katie collection after d days will be: 
As Katie wants to collect over 100 seashells, so the total number of shells collected in d days will be greater than 100. We can represent this information in an inequality as:
Therefore, the inequality can be used to find the number of days, d, it will take Katie to collect over 100 seashells.
Maybe a mistake? I havent seen a " been used before.
Given:
The figure of two quadrilaterals.
In 
In 
To find:
Whether the figures are congruent, similar or neither.
Solution:
Ratio of corresponding sides are:
Similarly,
And,
Clearly, 
.
All corresponding sides are not proportional.
Therefore, the figures are neither similar nor congruent. Hence, third option is correct.
Answer:
4
Step-by-step explanation:
Let y be the width of the rectangle
The length of the rectangle is 5 unit more than the width. This is written as:
Length = y + 5
Area = 36
Recall:
Area of rectangle = length x width
36 = (y + 5) x y
36 = y^2 + 5y
Rearrange the expression
y^2 + 5y — 36 = 0
To solve this problem by factorization, multiply the first term (i.e y^2) and last term ( i.e — 36) together. This gives — 36y^2
Next, find two factors of —36y^2 such that when we add them together it will result to the second term (5y). These factors are —4y and 9y. Now we substitute —4y and 9y in place of 5y in the equation. This is illustrated below:
y^2 + 5y — 36 = 0
y^2 —4y + 9y — 36 = 0
We factorize as follows:
y(y — 4) + 9(y —4) = 0
(y + 9) (y — 4) =0
y + 9 = 0 or y — 4 = 0
y = —9 or y = 4
Since the measurement can not be negative, therefore y (i.e the width) is 4
