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2 years ago

1. 50 W and 100 W lamps are designed for the same voltage. Which lamp has the higher filament resistance and why?

Physics

1 answer:

KiRa [710]2 years ago

5 0

Answer:

Look below.

Explanation:

1.) The resistance of a light bulb filament is effected by both length and cross-sectional area. Thicker wires have less resistance. A 120-Watt bulb has a greater current and a smaller resistance. Thus, a 120-Watt bulb must have a thicker filament than a 60-Watt bulb (assuming the lengths of the filaments are identical). We also think of lightbulbs in terms of their power ratings in watts. Let us compare a 25-W bulb with a 60-W bulb. Since both operate on the same voltage, the 60-W bulb must draw more current to have a greater power rating. Thus the 60-W bulb’s resistance must be lower than that of a 25-W bulb. If we increase voltage, we also increase power. For example, when a 25-W bulb that is designed to operate on 120 V is connected to 240 V, it briefly glows very brightly and then burns out. Precisely how are voltage, current, and resistance related to electric power?

2.) Energy transferred = 120 × 2 = 240 J. This equation can be rearranged to V = E ÷ Q. So voltage is energy transferred divided by charge.

3.) Power= Voltage × Current

4.) W=Pt

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PSYCHO15rus [73]

Answer:

$|\Delta v |=\sqrt{\frac{4Gm}{d} }$

Explanation:

Consider two particles are initially at rest.

Therefore,

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Now plugging the values we get

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