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zhuklara [117]
3 years ago
6

A system is a group of objects that’s analyzed as one unit. Consider a car moving along a road that has a flat section and a hil

l. The energy of the car at any given time is equal to the energy that its engine provides minus the energy that the car. When the car moves along the flat section, all of its energy is , which is calculated from its velocity and . When the car moves uphill, some of its energy is transformed to , which is calculated from its gravity, height, and .
Physics
1 answer:
vladimir1956 [14]3 years ago
8 0

Answer:

a) Em= K +U,  b) Em= K

Explanation:

The system in this case is formed by the mobilizes and the hill.

Let's write the expressions correctly and completely.

a) When the car moves in the path, the mechanical energy is the siua of the kinetic energy of the car and the potential energy of the car when going up the hill.

              Em = K + U

be) when the car moves in the flat part all the mechanical energy is formed by its kinetic energy that is calculated with the mass and speed of the car

             Em = K

c) When the car goes up the hill the energy the mechanical energy is conserved, but part of the kinetic energy is transformed into potential energy.

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A negative charge of - 2.0 C and a positive charge of 3.0 C are separated by 72 m. What is the force
lukranit [14]

Answer:

F= 10.4 x10^6 N

Explanation:

A/C to Coulomb's law

F = k q1 q2 / r^ 2

F = 9x 10^9 x 2 x 3 / 72^2

F= 10.4 x 10 ^6 N

5 0
3 years ago
Moving 2.0 coulombs of charge a distance of 6.0 meters from point A to point B within an electric field requires a 5.0-newton fo
amm1812

Answer:

15 V

Explanation:

Electric potential is given as the product of Electric field and distance. Mathematically:

V = E * r

Where E = Electric field

r = distance = 6m

Electric field, E, is:

E = F / q

Where F = Electric force = 5N

q = Electric charge = 2C

Therefore, electric potential will be:

V = (F * r) / q

V = (5 * 6) / 2

V = 15V

5 0
3 years ago
What is the velocity?
Blababa [14]

Answer:

B. 0.98 m/s

Explanation:

This is because we use the simple formula of dividing the distance by the time. In which case would be 13.69m (distance) divided by 13.92s (time) and we will get 0.983477011 or 0.98m/s (your answer)

I hope this made sense and hoped it helped. Good luck with your test luv :)

8 0
3 years ago
32. A ball is going to fall downward through a vacuum chamber. If it has maximum potential energy at the top and maximum kinetic
QveST [7]

Half maximum velocity occurs at the point of half maximum kinetic energy which is exactly halfway down.

<h3>Conservation of energy</h3>

The principle of conservation of energy states that energy can neither be created nor destroyed but can be converted from one form to another.

M.A = K.E + P.E

At the maximum height, the kinetic energy of the ball while potential energy is maximum.

At the half-way down, the ball kinetic energy of the ball is equal to the potential energy.

Thus, half maximum velocity occurs at the point of half maximum kinetic energy which is exactly halfway down.

Learn more about kinetic energy here: brainly.com/question/25959744

8 0
2 years ago
A car drives around a curve with radius 539 m at a speed of 32.0 m/s. The road is banked at 5.00°. The mass of the car is 1.40 ×
HACTEHA [7]

Answer:

f_r = 150.47 N

Explanation:

given,

r = 539 m

v = 32 m/s

road banked at = 5°

∑ F_x

\dfrac{mv^2}{r}= N sin \theta + f_r cos \theta

∑ F_y = 0

0 = N cos \theta - f_r sin \theta - mg

N = \dfrac{f_rsin \theta + mg}{cos \theta}

\dfrac{mv^2}{r}= (\dfrac{f_rsin \theta + mg}{cos \theta})sin \theta + f_r cos \theta

              = f_r sin \theta tan \theta + mg tan \theta + f_r cos \theta

        f_r = \dfrac{\dfrac{mv^2}{r}- mg tan\theta}{sin\theta tan \theta + cos \theta}

         f_r = \dfrac{\dfrac{1.4\times 10^3 \times 32^2}{539}- 1.4\times 10^{3}\times 9.8 \times 0.087}{0.087 \times 0.087 + 0.996}

f_r = 150.47 N

8 0
3 years ago
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