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Reika [66]
3 years ago
6

Simplify the expression.

Mathematics
2 answers:
BigorU [14]3 years ago
4 0
D) 1/m^18

Explanation:
(m^-2/m-1m5)^3
m^-6/m^-3m^15
1/m^6 / m^15/m^3
1/m^6 / m^12
1/m^6 (1/m^12)
1/m^18

let me know if you want clarification
iogann1982 [59]3 years ago
4 0

Answer:

D)\frac{1}{m^{18} }

Step-by-step explanation:

Multiply m^{-1} by m^{5} by adding the exponents.

Use the power rule a^{m} a^{n} =a^{m+n} to combine exponents.

(\frac{m^{-1+5} }{m^{-2} } )^{-3} \\

Add -1 and 5.

(\frac{m^{4} }{m^{-2} } )^{-3}

Move m^{-2} to the numerator using the negative exponent rule \frac{1}{b^{-n} } =b^{n}.

(m^{4} m^{2} )

Multiply m^{4} by m^{2} by adding the exponents.

Use the power rule a^{m} a^{n} =a^{m+n} to combine exponents.

(m^{4+2} )^{-3}

Add 4 and 2.

(m^{6} )^{-3}

Multiply the exponents in (m^6)^{-3}

Apply the rule and multiply exponents, (a^m)^n=a^{mn}.

m^{6*-3}

Multiply 6 by -3.

m^{-18}

Rewrite the expression using the negative exponent rule b^{-n} =\frac{1}{b^{n} }.

\frac{1}{m^{18} }

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nignag [31]

Answer:

The population density for the village and the estate together is 112.5 people per square kilometer.

Step-by-step explanation:

The statement is incorrectly written. Correct form is described below:

<em>A village has an area of 6 square kilometers and a population density of 600 people per square kilometer. An estate stituated next to the village has a population of 800 and a population density of 400 people per square kilometer. Work out the population density, in people per square kilometer, for the village and the state together. </em>

Dimensionally speaking, the population density of the village and the estate together (r), measured in people per square kilometer, is defined by this expression:

r = \frac{n_{V}+n_{E}}{A_{V}+A_{E}} (1)

Where:

n_{V}, n_{E} - Population of the village and the estate, measured in people.

A_{V}, A_{E} - Area of the village and the estate, measured in square kilometers.

First, we find the population of the village:

n_{V} = \frac{600\,\frac{p}{km^{2}} }{6\,km^{2}}

n_{V} = 100\,p

Then, we determine the area of the estate:

A_{E} = \frac{800\,p}{400\,\frac{p}{km^{2}} }

A_{E} = 2\,km^{2}

If we know that n_{V} = 100\,p, n_{E} = 800\,p, A_{V} = 6\,km^{2} and A_{E} = 2\,km^{2}, then the population density of the village and the estate together is:

r = \frac{100\,p+800\,p}{6\,km^{2}+2\,km^{2}}

r = 112.5\,\frac{p}{km^{2}}

The population density for the village and the estate together is 112.5 people per square kilometer.

4 0
3 years ago
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