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3 years ago

Which one of the following molecules is polar? PBr5 CCl4 BrF5 XeF2 XeF4

1 answer:

6 0

Polar molecules are characterized by unequal sharing of electrons in a molecule forming a partial negative and positive charges. For this case, the correct answer is the BrF5. It is has a free pair of electrons and the forces are not balanced.

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Which of the following is a characteristic science?

NikAS [45]

Answer:

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Explanation:

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2 years ago

Convert: 65 kg to mg 65,000 mg O 65,000,000 mg O 65 mg

makkiz [27]

Answer:

kg, mg. 65.00, 65,000,000. 65.01, 65,010,000. 65.02, 65,020,000. 65.03, 65,030,000. 65.04, 65,040,000. 65.05, 65,050,000. 65.06, 65,060,000.

Explanation:

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3 years ago

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Rainwater can have a ph as low as 3,meaning that it is very

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Rainwater can have a ph as low as 3, meaning that it is very C. Acidic

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3 years ago

What mass in grams of KCl (74.55 g/mol) is produced from 65.8 grams of KClO3 (122.55 g/mol) if the reaction has a yield of 67.2%

marishachu [46]

Y’all what is the answer

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3 years ago

A 37.2 g sample of copper at 99.8 °C is carefully placed into an insulated container containing 188 g of water at 18.5 °C. Calcu

klasskru [66]

Answer:

T₂ = 19.95°C

Explanation:

From the law of conservation of energy:

$Heat\ Lost\ by\ Copper = Heat\ Gained\ by\ Water\\m_cC_c\Delta T_c = m_wC_w\Delta T_w$

where,

mc = mass of copper = 37.2 g

Cc = specific heat of copper = 0.385 J/g.°C

mw = mass of water = 188 g

Cw = specific heat of water = 4.184 J/g.°C

ΔTc = Change in temperature of copper = 99.8°C - T₂

ΔTw = Change in temperature of water = T₂ - 18.5°C

T₂ = Final Temperature at Equilibrium = ?

Therefore,

$(37.2\ g)(0.385\ J/g.^oC)(99.8\ ^oC-T_2)=(188\ g)(4.184\ J/g.^oC)(T_2-18.5\ ^oC)\\99.8\ ^oC-T_2 = \frac{(188\ g)(4.184\ J/g.^oC)}{(37.2\ g)(0.385\ J/g.^oC)}(T_2-18.5\ ^oC)\\\\99.8\ ^oC-T_2 = (54.92) (T_2-18.5\ ^oC)\\54.92T_2+T_2 = 99.8\ ^oC + 1016.02\ ^oC\\\\T_2 = \frac{1115.82\ ^oC}{55.92}$

T₂ = 19.95°C

6 0

2 years ago