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Anit [1.1K]
3 years ago
6

A Mole of elephants would weigh how much more than the moon? I got 6.301x10^23 and set the problem up like this: 6.022x10^23 x 2

.268x10^3
Chemistry
1 answer:
Margaret [11]3 years ago
5 0

Answer:

The Moon weighs about 7.349*10^22 kg

How much does “an elephant” weigh? Grown-up elephants vary between 1.7 tons (small wood elephant cow) and 6 tons (big African elephant bull). Let us pick 2.720 tons or 2720 kg as an average weigh one, this is valid for Asian elephants.

A mole of elephants weighs 6.022 * 10^23 x 2720 kg = 1.638 * 10^27 kg.

That is 1,638 * 10^27 / 7,349*10^22 = 22289 times more.

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The vaporization of 1 mole of liquid water (system) at 100.9 C, 1.00 atm, is endothermic.
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Answer:

a) The work done is 10.0777 kJ

b) The water's change in internal energy is -122.1973 kJ

Explanation:

Given data:

1 mol of liquid water

T₁ = temperature = 100.9°C

P = pressure = 1 atm

Endothermic reaction

T₂ = temperature = 100°C

1 mol of water vapor

VL = volume of liquid water = 18.8 mL = 0.0188 L

VG = volume of water vapor = 30.62 L

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Q = heat added to the system = -40.7 kJ

Questions: a) Calculate the work done on or by the system, W = ?

b) Calculate the water's change in internal energy, ΔU = ?

Heat for 3.25 moles:

Q_{1} =3.25*(-40.7)=-132.275kJ

The work done:

W=-nP*delta(V)=-3.25*101.33*(0.0188-30.62)=10077.6637J=10.0777kJ

The change in internal energy:

delt(U)=W+Q_{1} =10.0777-132.275=-122.1973kJ

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Since water is a slow conductor of heat, it need more energy than the sand. so its temperature is increasing.  soil loses heat faster.  

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