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Answer:
Magnitude of force P = 25715.1517 N
Explanation:
Given - The wires each have a diameter of 12 mm, length of 0.6 m, and are made from 304 stainless steel.
To find - Determine the magnitude of force P so that the rigid beam tilts 0.015∘.
Proof -
Given that,
Diameter = 12 mm = 0.012 m
Length = 0.6 m
= 0.015°
Youngs modulus of elasticity of 34 stainless steel is 193 GPa
Now,
By applying the conditions of equilibrium, we have
∑fₓ = 0, ∑
= 0, ∑M = 0
If ∑
= 0
⇒
×0.9 - P × 0.6 = 0
⇒
×3 - P × 2 = 0
⇒
= 
If ∑
= 0
⇒
×0.9 = P × 0.3
⇒
×3 = P
⇒
= 
Now,
Area, A =
= 1.3097 × 10⁻⁴ m²
We know that,
Change in Length ,
= 
Now,
= 9.1626 × 10⁻⁹ P
= 1.83253 × 10⁻⁸ P
Given that,
= 0.015°
⇒
= 2.618 × 10⁻⁴ rad
So,

⇒2.618 × 10⁻⁴ = ( 1.83253 × 10⁻⁸ P - 9.1626 × 10⁻⁹ P) / 0.9
⇒P = 25715.1517 N
∴ we get
Magnitude of force P = 25715.1517 N
Answer:
p=15.097lbf/in^2
Explanation:
the manometric pressure is that in which the atmospheric pressure is not taken into account, so for this case only the pressure exerted by the water on the bus is calculated using the following equation.
P=ρgh
where
ρ=density of water at 55°F=999.4kg/m^3
g=9.81m/s^2
h=35ft=10.668m
Solving
P=(994.4)(9.81)(10.668)=104067.02Pa = 15.097lbf/in^2
the gage pressure does a skin diver experience when they dive to 35 ft is 15.097lbf/in^2