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NeTakaya
3 years ago
11

Water from the Earth's surface turns into a gas, or water vapor, when it is warmed and

Engineering
2 answers:
murzikaleks [220]3 years ago
8 0
The answer is evaporation.
bagirrra123 [75]3 years ago
4 0

Answer:

Evaporation.

Explanation:

Evaporation is the stage of the Water Cycle where water turns into water vapor. The steps following Evaporation in order include Condensation, Precipitation, and Transpiration.

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The major resisting force in gravity dam? ​
inna [77]

The self weight of dam.

6 0
3 years ago
Read 2 more answers
Consider a very long rectangular fin attached to a flat surface such that the temperature at the end of the fin is essentially t
zepelin [54]

Answer:

attached below

Explanation:

4 0
3 years ago
Water from the Earth's surface turns into a gas, or water vapor, when it is warmed and
bagirrra123 [75]

Answer:

Evaporation.

Explanation:

Evaporation is the stage of the Water Cycle where water turns into water vapor. The steps following Evaporation in order include Condensation, Precipitation, and Transpiration.

4 0
3 years ago
Read 2 more answers
A vector AP is rotated about the Z-axis by 60 degrees and is subsequently rotated about X-axis by 30 degrees. Give the rotation
Musya8 [376]

Answer:

R = \left[\begin{array}{ccc}1&0&0\\0&cos30&-sin30\\0&sin30&cos30\end{array}\right]\left[\begin{array}{ccc}cos 60&-sin60&0\\sin60&cos60&60\0&0&1\end{array}\right]

Explanation:

The mappings always involve a translation and a rotation of the matrix. Therefore, the rotation matrix will be given by:

Let \theta and \alpha be the the angles 60⁰ and 30⁰ respectively

that is \theta = 60⁰ and

\alpha = 30⁰

The matrix is given by the following expression:

\left[\begin{array}{ccc}1&0&0\\0&cos30&-sin30\\0&sin30&cos30\end{array}\right]\left[\begin{array}{ccc}cos 60&-sin60&0\\sin60&cos60&60\0&0&1\end{array}\right]

The angles can be evaluated and left in the surd form.

4 0
2 years ago
a cantilever beam 1.5m long has a square box cross section with the outer width and height being 100mm and a wall thickness of 8
djverab [1.8K]

Answer:

a) 159.07 MPa

b) 10.45 MPa

c) 79.535 MPa

Explanation:

Given data :

length of cantilever beam = 1.5m

outer width and height = 100 mm

wall thickness = 8mm

uniform load carried by beam  along entire length= 6.5 kN/m

concentrated force at free end = 4kN

first we  determine these values :

Mmax = ( 6.5 *(1.5) * (1.5/2) + 4 * 1.5 ) = 13312.5 N.m

Vmax = ( 6.5 * (1.5) + 4 ) = 13750 N

A) determine max bending stress

б = \frac{MC}{I}  =  \frac{13312.5 ( 0.112)}{1/12(0.1^4-0.084^4)}  =  159.07 MPa

B) Determine max transverse shear stress

attached below

   ζ = 10.45 MPa

C) Determine max shear stress in the beam

This occurs at the top of the beam or at the centroidal axis

hence max stress in the beam =  159.07 / 2 = 79.535 MPa  

attached below is the remaining solution

6 0
3 years ago
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