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belka [17]
3 years ago
8

Freon-11, CCl3F has been commonly used in air conditioners. It has a molar mass of 137.35 g/mol and its enthalpy of vaporization

is 24.8 kJ/mol at its normal boiling point of 24C. Ideally how much energy in the form of heat is removed from a room by an air conditioner that evaporates 1.00 kg of freon-11?
Chemistry
1 answer:
PilotLPTM [1.2K]3 years ago
0 0

Answer:

180.56 Kilo joules of energy is removed in the form of heat when 1.00 kg of freon-11 is evaporated.

Explanation:

Molar mass of freon-11 = 137.35 g/mol

Enthalpy of vaporization of freon-11= \Delta H_{vap}=24.8 kJ/mol

Mass of freon-11 evaporated = 1.00 kg = 1000 g

Moles of freon-11 evaporated = \frac{1000 g}{137.35 g/mol}=7.2807 mol

Energy in the form of heat removed when 1.00 kg of freon-11 gets evaporated:

7.28067 mol\times \Delta H_{vap}=7.2807 mol\times 24.8 kJ/mol

=180.56 kJ

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To determine the number of moles of air present in the tank, we assume that air is an ideal gas in order for us to use the following equation,
                                        n = PV/RT
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8 0
3 years ago
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So, litmus paper is a qualitative tool for assessing the acidity or basicity of a substance (usually a solution). In general, blue litmus turns red in the presence of an acid, and red litmus turns blue in the presence of a base. They can't really tell you much more than that.

The solutions that are most likely acids are those that turn blue litmus red <em>and </em>do not evoke a color change in red litmus. A solution that turns red litmus blue <em>or </em>does not evoke a color change in blue litmus is likely not an acid. Using these criteria, solutions 4 and 7 are most likely acids since they both turn blue litmus red (and they cause no color change in red litmus).

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2 years ago
Iridium-192 is used in medicine to treat prostate cancer. Iridium-192 has two modes of radioactive decay: 96% of the time it dec
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Answer:

The daughter nuclides of these two decay processes are ^{192}_{78}Pt and ^{192}_{76}Os.

Explanation:

The beta emission is represented by:

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Then, the daughter nuclide of the electron capture of Ir-192 is:

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Therefore, the daughter nuclides of these two decay processes are ^{192}_{78}Pt and ^{192}_{76}Os.

I hope it helps you!

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