First, we will use the general gas formula to get the number of moles.
PV = nRT where:
P is the pressure of gas = 751 mmHg = 100125.096375 Pascal
V is the volume = 1 liter = 0.001 m^3
n is the number of moles we want to calculate
R is the gas constant = <span>8.314 J/(K. </span>mol<span>)
T is the temperature = 31 degrees celcius = </span>304.15 degree kelvin
Substitute in the above equation to get the number of moles as follows:
100125.096375 * 0.001 = n * 8.314 * 304.15
n = 0.039595 moles
Now, we will use the number of moles to get the mass as follows:
number of moles = mass / molar mass
mass = number of moles * molar mass
number of moles = 0.039595 moles
molar mass of ammonia (NH3) = 14 + 3(1) = 17 grams
Substitute to get the mass as follows:
mass = 0.039595 * 17 = 0.673122 grams
Last step is to get the density as follows:
density = mass / volume
mass = 0.673122 grams
volume = 1 liter
density = 0.673122 / 1 = 0.673122 grams/liter = <span>0.000675 kg/L</span>
Answer:
All exothermic reactions _c.release energy____
Explanation:
Exothermic reactions are those that give off energy, for example in the form of heat in combustion (it has a negative enthalpy variation, the energy of the products being less than the energy of the reagents)
Finding the volume of regular geometric objects uses standard formulas. The volume of a box equals length times width times height, for example. Not every object, however, fits a formula. Water displacement is best only used for irregular shaped objects.
Answer:
ΔH = +26.08 kJ/mol
Explanation:
The change in enthalpy (ΔH) is given in J/mol, and can be calculated for dissolution by the equation:
ΔH = m(water)*Cp*ΔT/n(solute)
The mass of water is the density multiplied by the volume
m = 1g/mL * 25.0mL = 25.0 g
The number of the moles is the mass divided by the molar mass. Knowing the molar masses of the elements:
N = 14 g/mol x 2 = 28
H = 1 g/mol x 4 = 4
O = 16 g/mol x 3 = 48
NH₄NO₃ = 80 g/mol
n = 1.25/80 = 0.015625 mol
So,
ΔH = 25*4.18*(25.8 - 21.9)/0.015625
ΔH = 26,083.2 J/mol
ΔH = +26.08 kJ/mol