1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
LekaFEV [45]
3 years ago
15

an aqueous solution has a mass of 490 grams containing 8.5×5103 gram of calcium ions. the concentration of calcium ions is in th

is solution is
Chemistry
1 answer:
Alex777 [14]3 years ago
8 0
There are several various of expressing concentration. For instance, mass percent, volume percent, Molarity, Normality, Molality, etc.

In present case, weight of solute and solvent are given, so it will be convenient to express concentration in terms of mass percent.

Given: weight of solute (Ca2+) = 8500 g
weight of solvent (water) = 490 g.
Therefore, mass of solution = 8500 + 490 = 8990 g

Now, mass percent = \frac{\tect{Weight of solute}}{\text{Weight of solution}} X 100
                               = \frac{\tect{8500}}{\text{8990}} X 100
                               = 94.55 %

Answer: Concentration of calcium ions is in this solution is 94.55 % (w/W)
You might be interested in
Urea, (NH2)2CO, is a product of metabolism of proteins. An aqueous solution is 37.2% urea by mass and has a density of 1.032 g/m
Feliz [49]

Answer:

The molarity of urea in this solution is 6.39 M.

Explanation:

Molarity (M) is <em>the number of moles of solute in 1 L of solution</em>;  that is

molarity = moles of solute ÷ liters of solution

To calculate the molality, we need to know the number of moles of urea and the volume of solution in liters. We assume 100 grams of solution.

Our first step is to calculate the moles of urea in 100 grams of the solution,

using the molar mass a conversion factor. The total moles of 100g of a 37.2 percent by mass solution is

60.06 g/mol ÷ 37.2 g = 0.619 mol

Now we need to calculate the volume of 100 grams of solution, and we use density as a conversion factor.

1.032 g/mL ÷ 100 g = 96.9 mL

This solution contains 0.619 moles of urea in 96.9 mL of solution. To express it in molarity, we need to calculate the moles present in 1000 mL (1 L) of the solution.

0.619 mol/96.9 mL × 1000 mL= 6.39 M

Therefore, the molarity of the solution is 6.39 M.

4 0
3 years ago
JWhat type of evidence is gathering information through your senses or using scientific tools?
Ad libitum [116K]
Observations etc etc
8 0
2 years ago
The air bags in cars are inflated when a collision triggers the explosive, highly exothermic decomposition of sodium azide (NaN3
Oksanka [162]

Answer : The mass of NaN_3 required is, 166.4 grams.

Explanation :

First we have to calculate the moles of nitrogen gas.

Using ideal gas equation:

PV=nRT

where,

P = Pressure of N_2 gas = 1.00 atm

V = Volume of N_2 gas = 113 L

n = number of moles N_2 = ?

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of N_2 gas = 85^oC=273+85=358K

Putting values in above equation, we get:

1.00atm\times 113L=n\times (0.0821L.atm/mol.K)\times 358K

n=3.84mol

Now we have to calculate the moles of sodium azide.

The balanced chemical reaction is,

2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)

From the balanced reaction we conclude that

As, 3 mole of N_2 produced from 2 mole of NaN_3

So, 3.84 moles of N_2 produced from \frac{2}{3}\times 3.84=2.56 moles of NaN_3

Now we have to calculate the mass of NaN_3

\text{ Mass of }NaN_3=\text{ Moles of }NaN_3\times \text{ Molar mass of }NaN_3

Molar mass of NaN_3 = 65 g/mole

\text{ Mass of }NaN_3=(2.56moles)\times (65g/mole)=166.4g

Therefore, the mass of NaN_3 required is, 166.4 grams.

3 0
3 years ago
It is normal to heal after having sex :c?
zheka24 [161]

Answer:

ayo?

Explanation:

3 0
2 years ago
The Spirit of America Goodyear blimp has a volume of 2.027×105 ft3. Convert this volume to an SI unit with the basic unit L.
Rus_ich [418]

Answer:

             5.73 × 10⁶ L

Solution:

                    As we know one cubic foot is equal to 28.3168 L. Using this relation we can convert 2.027 × 10⁵ ft³ into L as,

                                                 1 ft³  =  28.3168 L

So,

                                              2.027 × 10⁵ ft³  =  X L

Solving for X,

                     X =  (2.027 × 10⁵ ft³ × 28.3168 L) ÷ 1 ft³

                     X  =  5.73 × 10⁶ L

3 0
3 years ago
Other questions:
  • The halogens like to bond with what other group?
    7·1 answer
  • What is the basic (smallest) unit of matter
    5·1 answer
  • Explain how plastic can be both beneficial and detrimental at the same time.
    8·1 answer
  • Calculate the predicted density for calcium, ca, given the density of strontium, sr, (2.63g/cm3) and barium, ba, (3.65 g/cm3).
    8·1 answer
  • Name:_____________________________________________________ Date:___________ Period:_________ 3/23 - 3/27 Assignment 1: Gas Law P
    9·1 answer
  • What is the formula for calculating the speed
    12·2 answers
  • 672cm x 11cm / 6.3cm^3
    8·2 answers
  • What kind of change forms a new substance?<br><br> A physical change
    12·2 answers
  • Why does the total volume of water and alcohol decrease when the liquids were mixed together?
    5·2 answers
  • A Herbig-Haro (HH) object is:_:_________.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!