Question

A baseball goes from zero to 34 m/s in 0.188 s. What is its average acceleration? Answer in units of m/s^2

Answer 1

Answer:

$a_{avg} = 180.85 m/s^{2}$

Given:

Initial velocity, u = 0 m/s

Final velocity, v = 34 m/s

Time interval, $\Delta t = 0.188 s$

Solution:

Acceleration is the rate at which the velocity of an object changes.

Thus

Average acceleration, $a_{avg} = \frac{\Delta v}{\Delta t}$

$a_{avg} = \frac{v - u}{t - 0} = \frac{34 - 0}{0.188} = 180.85 m/s^{2}$