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laiz [17]
3 years ago
6

Calculate the solubility of carbon dioxide in water at an atmospheric pressure of 0.400 atm (a typical value at high altitude).

Chemistry
1 answer:
likoan [24]3 years ago
5 0

Answer:

1.40*10⁻² M

Explanation:

We have the solubility formula

Solubility,

S = KH*P  

where

KH = measure of hardness of water / carbonate hardness = 3.50*10⁻² mol/L.atm

P = atmospheric pressure = 0.400 atm

Hence, we have

S = KH*P

= (3.50*10⁻² mol/L.atm)*(0.400 atm)

= 1.40*10⁻² mol/L

But 1 mol/L = 1 M,

Hence, the answer (1.40*10⁻² mol/L ) is equivalent to

= 1.40*10⁻² M

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Generally how does the first ionization energy vary as the atomic number increases going across a period
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Explanation:

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Classify the chemical equations as being balanced or not balanced. 2CO 2NO → 2CO2 N2 6CO2 6H2O → C6H12O6 O2 H2CO3 → H2O CO2 2Cu
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Answer:

2CO 2NO → 2CO2 N2 : Balanced

6CO2 6H2O → C6H12O6 : Unbalanced

H2CO3 → H2O CO2 : Balanced

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Explanation:

1.) 2CO 2NO → 2CO2 N2

2 Carbon 2

4 Oxygen 4

2 Nitrogen 2

The amount of atoms of each element on each side of the equation are the same therefore the equation is balanced.

2.) 6CO2 6H2O → C6H12O6 O2

6 Carbon 6

12 Oxygen 8

12 Hydrogen 12

The amount of oxygen atoms is different on both sides of the equation therefore the equation is not balanced.

3.) H2CO3 → H2O CO2

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1 Carbon 1

3 Oxygen 3

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2 Cu 2

2 O 1

The amount of oxygen atoms is different on both sides of the equation therefore the equation is not balanced.

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