Answer:
v = 2.85 m/s
Explanation:
By the law of similarity of the triangle we can say
here we know that
height of man = 2 m
let the distance of man from spotlight = x
distance of wall from spotlight = 12 m
height of image is let say "y"
so we will have
now we have
here we know
x = 4 m
now we have
Answer:
The work done by Joe, W_joe, when he raises the barbell to finish one repetition is 211.98J
The correct option is Wsam <W_Joe.
Explanation:
From the mass of the bar, the acceleration of gravity and the distance that the bar travels in each of them when performing the lifting movement from the chest you can calculate the work done by each one:
W_joe= 31.5kg × 9.81 (m/s^{2} ) × 0.686m = 211.98J
W_sam= 31.5kg × 9.81 (m/s^{2} ) × 0.608m = 187.88J
187.88J < 211.98J ⇒ Wsam <W_Joe
Answer:
The minimum coefficient of friction is 0.544
Solution:
As per the question:
Radius of the curve, R = 48 m
Speed of the car, v = 16 m/s
To calculate the minimum coefficient of static friction:
The centrifugal force on the box is in the outward direction and is given by:
where
= coefficient of static friction
The net force on the box is zero, since, the box is stationary and is given by:
I don understand this language. but i tried to search the language you wrote in and an answer came so there it is... That answer is only for question 2 :)
Good luck hope i helped <3