Question

•6.5 L of a gas has a pressure of 840 mmHg and temperature of 84 0C. What will be its volume at STP

Answer 1

Answer:

5.5 L

Explanation:

Step 1: Given data

• Initial volume (V₁): 6.5 L

• Initial pressure (P₁): 840 mmHg

• Initial temperature (T₁): 84 °C

• Final volume (V₂): ?

• Final pressure (P₂): 760 mmHg (standard pressure)

• Final temperature (T₂): 273.15 K (standard temperature)

Step 2: Convert T₁ to Kelvin

We will use the following expression.

K = °C + 273.15

K = 84 °C + 273.15 = 357 K

Step 3: Calculate the final volume of the gas

We will use the combined gas law.

P₁ × V₁ / T₁ = P₂ × V₂ / T₂

V₂ = P₁ × V₁ × T₂ / T₁ × P₂

V₂ = 840 mmHg × 6.5 L × 273.15 K / 357 K × 760 mmHg = 5.5 L