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3 years ago

Given the equation for a system at equilibrium:

Chemistry

1 answer:

zlopas [31]3 years ago

6 0

Answer: 1. $NH_3$ increases.

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

For the given equation:

$N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)+energy$

If the concentration of $N_2$ is increased , according to the Le-Chatlier's principle, the reaction has to shift to right or forward direction. In order to do that the concentration of products has to increase.

Thus the concentration of $NH_3$ increases.

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When you are balancing chemical reactions ('equations'), what must you never touch?

timofeeve [1]

You should never touch the subscripts, as that will change the composition. Hope I helped!

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3 years ago

Read 2 more answers

When two clear, colourless liquids are mixed together, a yellow precipitate is formed. This is an example of a

Flura [38]

Answer:

Combining the two clear colorless liquids is a chemical change.

Explanation:

Because a different solid substance is formed. Tell students that a precipitate is an insoluble solid that forms when two solutions are combined and react chemically. Insoluble means that the solid will not dissolve.

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2 years ago

100 points !!!! Write your answer beside each number. You should have 13 items labeled in all.

Arte-miy333 [17]

Answer:

Explanation:

1) Valence electrons

2) Electrons

3) 2 electrons on K-shell

4) 8 electrons on L-Shell

5) 18 electrons on M-shell

6) nucleus

7) Proton

8) neutron

9) principal energy level

10) atomic number

11) symbol of the atom

12) name of the atom

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3 years ago

For the reaction CO2(g) + H2(g)CO(g) + H20(g)

Studentka2010 [4]

Answer:

The ΔG° is 29 kJ and the reaction is favored towards reactant.

Explanation:

Based on the given information, the ΔH°rxn or enthalpy change is 41.2 kJ, the ΔS°rxn or change in entropy is 42.1 J/K or 42.1 * 10⁻³ kJ/K. The temperature given is 289 K. Now the Gibbs Free energy change can be calculated by using the formula,

ΔG° = ΔH°rxn - TΔS°rxn

= 41.2 kJ - 289 K × 42.1 × 10⁻³ kJ/K

= 41.2 kJ - 12.2 kJ

= 29 kJ

As ΔG° of the reaction is positive, therefore, the reaction is favored towards reactant.

5 0

2 years ago

For the Zn - Cu^2+ voltaic cell Zn(s) + Cu^2+(aq, 1M) + Cu(s) E degree _cell = 1.10 V Given that the standard reduction potentia

Fittoniya [83]

Answer : The value of $E^o_{(Cu^{2+}/Cu)}$ is, 0.34 V

Explanation :

Here, copper will undergo reduction reaction will get reduced. Zinc will undergo oxidation reaction and will get oxidized.

The oxidation-reduction half cell reaction will be,

Oxidation half reaction: $Zn\rightarrow Zn^{2+}+2e^-$

Reduction half reaction: $Cu^{2+}+2e^-\rightarrow Cu$

Oxidation reaction occurs at anode and reduction reaction occurs at cathode. That means, gold shows reduction and occurs at cathode and chromium shows oxidation and occurs at anode.

The overall balanced equation of the cell is,

$Zn+Cu^{2+}\rightarrow Zn^{2+}+Cu$