Answer:
V = 36.7L of ![N_{2}](https://tex.z-dn.net/?f=N_%7B2%7D)
Explanation:
1. Write the chemical reaction for the decomposition of sodium azide:
![_{2}NaN_{3}(l)=_{2}Na(s)+_{3}N_{2}(g)](https://tex.z-dn.net/?f=_%7B2%7DNaN_%7B3%7D%28l%29%3D_%7B2%7DNa%28s%29%2B_%7B3%7DN_%7B2%7D%28g%29)
2. Find the number of moles of
produced by the decomposition of 71.4g of
:
![71.4gNaN_{3}*\frac{1molNaN_{3}}{65gNaN_{3}}*\frac{3molesN_{2}}{2molesNaN_{3}}=1.65molesN_{2}](https://tex.z-dn.net/?f=71.4gNaN_%7B3%7D%2A%5Cfrac%7B1molNaN_%7B3%7D%7D%7B65gNaN_%7B3%7D%7D%2A%5Cfrac%7B3molesN_%7B2%7D%7D%7B2molesNaN_%7B3%7D%7D%3D1.65molesN_%7B2%7D)
3. Use the ideal gas equation to find the Volume of
occupied by 1.65 moles of
, at the temperature and pressure given by the problem:
![PV=nRT](https://tex.z-dn.net/?f=PV%3DnRT)
Solving for V:
![V=\frac{nRT}{P}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7BnRT%7D%7BP%7D)
Converting the temperature from ◦C to K:
25◦C+273.15=298.15K
Replacing values:
![V=\frac{1.65mol*(0.082\frac{atm.L}{mol.K})*298.15K}{1.10atm}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1.65mol%2A%280.082%5Cfrac%7Batm.L%7D%7Bmol.K%7D%29%2A298.15K%7D%7B1.10atm%7D)
V=36.7L of ![N_{2}](https://tex.z-dn.net/?f=N_%7B2%7D)
Answer:
B
Explanation:
Trust me I've had problems like these
Answer:
<h2>1.89 atm</h2>
Explanation:
The new volume can be found by using the formula for Boyle's law which is
![P_1V_1 = P_2V_2](https://tex.z-dn.net/?f=P_1V_1%20%3D%20P_2V_2)
Since we are finding the new volume
![V_2 = \frac{P_1V_1}{P_2} \\](https://tex.z-dn.net/?f=V_2%20%3D%20%20%5Cfrac%7BP_1V_1%7D%7BP_2%7D%20%20%5C%5C)
From the question we have
![V_2 = \frac{1.23 \times 23}{15} = \frac{28.29}{15} \\ = 1.886](https://tex.z-dn.net/?f=V_2%20%3D%20%20%5Cfrac%7B1.23%20%5Ctimes%2023%7D%7B15%7D%20%20%3D%20%20%5Cfrac%7B28.29%7D%7B15%7D%20%20%5C%5C%20%20%3D%201.886)
We have the final answer as
<h3>1.89 atm</h3>
Hope this helps you