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The final molarity of HCl is 2.284 M
We'll begin by listing what was given from the question. This is shown below:
Initial volume (V₁) = 5.56 mL
Initial Molarity (M₁) = 4.108 M
Final volume (V₂) = 5.56 + 4.44 = 10 mL
<h3>Final Molarity (M₂) =? </h3>
The final molarity of the HCl solution can be obtained by using the dilution formula as illustrated below:
<h3>M₁V₁ = M₂V₂</h3>
4.108 × 5.56 = M₂ × 10
22.84048 = M₂ × 10
Divide both side by 10
M₂ = 22.84048 / 10
<h3>M₂ = 2.284 M</h3>
Therefore, final molarity of the HCl solution is 2.284 M.
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Answer:
A one-step mechanism involving a transition state that has a carbon partially bonded to both chlorine and oxygen
Explanation:
The compound CH3Cl is methyl chloride. This is a nucleophilic substitution reaction that proceeds by an SN2 mechanism. The SN2 mechanism is a concerted reaction mechanism. This means that the departure of the leaving group is assisted by the incoming nucleophile. The both species are partially bonded to opposite sides of the carbon atom in the transition state.
Recall that an SN2 reaction is driven by the attraction between the negative charge of the nucleophile (OH^-) and the positive charge of the electrophile (the partial positive charge on the carbon atom bearing the chlorine leaving group).
The standard enthalpy of reaction should be negative.
<h3>What is enthalpy?</h3>
A thermodynamic quantity equivalent to the total heat content of a system. It is equal to the internal energy of the system plus the product of pressure and volume.
Inside the heat pack are two chemicals that get mixed when you smush them together. As they mix, some weak bonds are broken, which takes a little bit of energy. But new, stronger bonds form which release energy. Releasing that energy causes the surroundings to heat up.
Hence, option B is correct.
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C) elements from the top left and the top right of the periodic table