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Hey there!
Na + FeBr₂ → NaBr + Fe
Firstly, balance Br.
Two on the left, one on the right. Add a coefficient of 2 in front of NaBr.
Na + FeBr₂ → 2NaBr + Fe
Next, balance Na.
One on the left, two on the right. Add a coefficient of 2 in front of Na.
2Na + FeBr₂ → 2NaBr + Fe
Lastly, balance Fe.
One on the left, one on the right. Already balanced.
Our final balanced equation:
2Na + FeBr₂ → 2NaBr + Fe
Hope this helps!
Answer:
5.19 m³
Explanation:
Data Given:
initial Pressure P1 = atmospheric pressure
Reported atmospheric pressure = 14.696 psi
Final pressures P2 = 68 psi
initial Temperature T1 = 26 °C
final Temperature T2 = 48 °C
initial Volume V1= 13 m³
final Volume V2 = ?
Solution:
Formula will be used
P1 V1 / T1 = P2 V2 / T2
To calculate volume rearrange the above formula
V2 = (P1 V1) T2 / T1 P2 . . . . . . . .(1)
put values in equation 1
V2 = (14.696 psi x 13 m³) 48 °C / 26 °C x 68 psi
V2 = (191.05 psi m³) 48 °C / 1768 °C psi
V2 = (9170.3 psi m³ °C / 1768 °C psi
V2 = 5.19 m³
So, final volume is 5.19 m³
n=m/M
8.0g÷58.10g/mol=0.14mol
V=n/c
0.14mol÷0.89M=0.16L=1.6×10²mL
hola amigos como están bien""
