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scoray [572]
3 years ago
8

How did Rutherford's gold foil experiment show that Thomson's plum pudding model of the atom was

Chemistry
1 answer:
Ket [755]3 years ago
6 0

Answer:

He blasted alpha rays at the gold foils. The Alpha rays are charged positive. When he blasted them the protons deflected and changed the course of them and the electrons surrounding the atom let them through. In the plum pudding model they were supposed to be sprinkled on which was clearly wrong according to that experiment.

Explanation:

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Draw the curved arrow mechanism for the reaction between (2S,3S)-3,5-dimethylhexan-2-ol and PCl3. Note the specific instructions
Vikki [24]

Answer:

(2R,3S)-2-chloro-3,5-dimethylhexane

Explanation:

As first step we have the <u>attack of the OH group</u> to the P atom in the PCl3 and one of the Cl atoms would leave. Then we will have a <u>rearrangement</u> to produce a <u>double bond </u>with the oyxgen on the OH. Finally the Cl produced will a<u>ttack the carbon</u> in a <u>Sn2 substitution reaction</u> to produce the halide with an <u>opposite configuration</u>.

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Indicate the pH value as pH &lt; 7, pH = 7 or PH &gt; 7 for each of the following substances.
Galina-37 [17]

Explanation:

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3 years ago
Boron sulfide, B2S3(s), reacts violently with water to form dissolved boric acid (H3BO3) and hydrogen sulfide gas.Express your a
ioda

Answer:

Explanation:

From the statement of the problem,

  B₂S₃_{s} + H₂O_{l}  →  H₃BO₃_{aq} + H₂S_{g}

              B₂S₃ + H₂O  →  H₃BO₃ + H₂S

We that the above expression does not conform with the law of conservation of mass:

To obey the law, we need to derive a balanced reaction equation:

   Let us use the mathematical method to obtain a balanced equation.

let the balanced equation be:

                        aB₂S₃ + bH₂O  →  cH₃BO₃ + dH₂S

where a, b, c and d will make the equation balanced.

  Conservating B: 2a = c

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                          H: 2b = 3c + 2d

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   if a = 1,

      c = 2,

      b = 6,

      2d = 2(6) - 3(2) = 6, d = 3

Now we can input this into our equation:

                     B₂S₃ + 6H₂O  →  2H₃BO₃ + 3H₂S

    B₂S₃_{s} + 6H₂O_{l}  →  2H₃BO₃_{aq} + 3H₂S_{g}

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