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ZanzabumX [31]
2 years ago
15

One way to identify the type of radioactive decay produced in a reaction is to pass the emission through an electric field Descr

ibe the type of radioactive emission produced from the decay of uranium- 238 to thorium-234 and its reaction to the electric field
A) Radioactive gamma decay is produced by the reaction. This neutral electromagnetic radiation are not attracted to the electric field

B) Beta particles are released during the radioactive decay. These negative particles are attracted to the positive plate in the electric field.

C) During the radioactive decay, alpha particles are released. These positive particles are attracted to the negative plate in the electric field.

D) Both types of radioactive emissions, particles and electromagnetic radiation are produced during this decay. None of these are attracted to the electric field
Chemistry
1 answer:
Elena L [17]2 years ago
5 0

Decay of Uranium-238 produces gamma radiaton whereas decay of thorium-234 releases beta radiation.

<h3>What type of radiation is produced?</h3>

In the decay of U-238, two gamma rays of different energies are emitted in addition to the alpha particle while on the other hand, in the decay of thorium-234 , beta rays are emitted.

So we can conclude that decay of Uranium-238 produces gamma radiaton whereas decay of thorium-234 releases beta radiation.

Learn more about decay here: brainly.com/question/25537936

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<u>Given:</u>

The initial energy of the electron Einitial = 16.32 * 10⁻¹⁹ J

The energy released i.e the change in energy ΔE = 5.4 * 10⁻¹⁹ J

<u>To determine:</u>

The final energy state Efinal of the electron

<u>Explanation:</u>

Since energy is being released, this suggests that Efinal < Einitial

i.e. ΔE = Einitial - Efinal

Efinal = Einitial - ΔE = (16.32 - 5.4)*10⁻¹⁹ = 10.92 * 10⁻¹⁹ J

Ans: A)

The electron moved down to an energy level and has an energy of 10.92 * 10⁻¹⁹ J

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