Answer:
4
Explanation:
pH=-log(H3O+)
- Hope that helps! Please let me know if you need further explanation.
Answer:
3.97× 10²³ atoms of Ag
Explanation:
Given data:
Mass of Ni = 112 g
Mass of AgNO₃ = 112 g
Atoms of silver produced = ?
Solution:
Chemical equation:
Ni + 2AgNO₃ → 2Ag + Ni(NO₃)₂
Number of moles of Ni:
Number of moles = mass/ molar mass
Number of moles = 112 g/58.7 g/mol
Number of moles = 2 mol
Number of moles of AgNO₃:
Number of moles = mass/ molar mass
Number of moles = 112 g/169.87 g/mol
Number of moles = 0.66 mol
Now we will compare the moles of Ag with both reactants.
AgNO₃ : Ag
2 : 2
0.66 : 0.66
Ni : Ag
1 : 2
2 ; 2×2= 4 mol
Number of moles of Ag produce by AgNO₃ are less so it will limiting reactant and limit the yield of Ag.
I mole = 6.022 × 10²³ atoms
0.66 mol × 6.022 × 10²³ atoms / 1 mol
3.97× 10²³ atoms of Ag
Answer: Titration
Explanation:
Titration is a method of quantitative analysis, by which a student, with standard volumetric equipment, burettes, and pipettes, can achieve very precise, and accurate results. It is also known as
volumetric analysis
.
Answer:
41.9(w/w) %
Explanation:
Based on the reaction:
Na₂C₂O₄(s) + 2HCl(aq) → H₂C₂O₄(aq) + 2NaCl(aq)
<em>Where 1 mole of sodium oxalate reacts with 2 moles of HCl</em>
Moles of HCl solution to reach end point are:
44.15mL = 0.04415L ₓ (0.250mol / L) = 0.01104 moles of HCl
As 2 moles of HCl reacts per mole of Na₂C₂O₄:
0.01104mol HCl ₓ (1 mol Na₂C₂O₄ / 2 mol HCl) = <em>5.519x10⁻³ moles Na₂C₂O₄</em> are in the sample.
Molar mass of Na₂C₂O₄ is 134g/mol; thus, mass of 5.519x10⁻³ moles Na₂C₂O₄ is:
5.519x10⁻³ moles Na₂C₂O₄ ₓ (134g / mol) = <em>0.740g of Na₂C₂O₄</em> in the sample.
Thus, percent by mass of sodium oxalate in the sample is:
0.740g of Na₂C₂O₄ / 1.766g ₓ 100 =
<h3>41.9(w/w) %</h3>
Crude oil, commonly known aspetroleum<span>, is a liquid </span>found<span> within the Earth comprised of hydrocarbons, organic compounds and small amounts of metal. Hope this helps</span>