________ delivers the precise number of parts to be assembled into a finished product at precisely the right time.

How do Consumers sometimes interact with a producers?

Vika [28.1K]

I really don’t know good luck

7 0

3 years ago

1. Design a circuit, utilizing set/reset coils where PB 1 starts Motor 1 and PB2 stops Motor 1. Pressing and releasing either pu

lianna [129]

Answer:

Circuit attached with explanation

Explanation:

Hi Dear,

A circuit is attached for your reference.

When you press "start" PB, the supply reaches the motor starter relay coil "M" that is also in parallel with the "start" PB which allows the motor to remain ON even when you release "start" PB as supply to relay coil is directly from supply "L" through "M".

To stop motor just press "stop" PB and the circuit breaks which de-energize the relay coil and the motor stops.

Hope this finds easy to you.

5 0

2 years ago

Write a program that removes all spaces from the given input. You may assume that the input string will not exceed 50 characters

GrogVix [38]

Answer:

Program that removes all spaces from the given input

Explanation:

// An efficient Java program to remove all spaces

// from a string

class GFG

{

// Function to remove all spaces

// from a given string

static int removeSpaces(char []str)

{

// To keep track of non-space character count

int count = 0;

// Traverse the given string.

// If current character

// is not space, then place

// it at index 'count++'

for (int i = 0; i<str.length; i++)

if (str[i] != ' ')

str[count++] = str[i]; // here count is

// incremented

return count;

}

// Driver code

public static void main(String[] args)

{

char str[] = "g eeks for ge eeks ".toCharArray();

int i = removeSpaces(str);

System.out.println(String.valueOf(str).subSequence(0, i));

}

5 0

3 years ago

Read 2 more answers

An automobile weighing 2500 lbf increases its gravitational potential energy by a magnitude of 2.25 × 104 Btu in going from an e

Mila [183]

Answer:

The elevation at the high point of the road is 12186.5 in ft.

Explanation:

The automobile weight is 2500 lbf.

The automobile increases its gravitational potential energy in $2.25 * 10^4 BTU$ . It means the mobile has increased its elevation.

The initial elevation is of 5183 ft.

The first step is to convert Btu of potential energy to adequate units to work with data previously presented.

British Thermal Unit - $1 BTU = 778.17 lbf*ft$

$2.25 * 10^4 BTU (\frac{778.17 lbf*ft}{1BTU} ) = 1.75 * 10^7 lbf * ft$

Now we have the gravitational potential energy in lbf*ft. Weight of the mobile is in lbf and the elevation is in ft. We can evaluate the expression for gravitational potential energy as follows:

$Ep = m*g*(h_2 - h_1)\\ W = m*g$