Answer:
The best way to ensure that OSHA will conduct a site inspection is by the submission a signed (by a current employee or employee representative) Formal Written complaints following OSHA guidelines (which can be found in the Council of Safety and Health (COSH) website) which will enable the commencement of process for an on site inspection
As such it is advisable to go through the following procedure before, filing a complaint
1) Talk to your workers union about the hazard
2) If you do not belong to a union, talk to your co-workers
3) Inform your employer who has responsibility for on the job safety
4) Speak or have a meeting with OSHA so as to receive guidance before filing a complaint
Explanation:
All of them
explanation:
you don’t need one
Answer:
Explanation:
= Area of section 1 = 
= Velocity of water at section 1 = 100 ft/min
= Specific volume at section 1 = 
= Density of fluid = 
= Area of section 2 = 
Mass flow rate is given by
The mass flow rate through the pipe is
As the mass flowing through the pipe is conserved we know that the mass flow rate at section 2 will be the same as section 1
The speed at section 2 is .
Answer:
The minimum particle diameter that is removed at 85% is 1.474 * 10 ^⁻4 meters.
Solution
Given:
Length = 48 m
Width = 12 m
Depth = 3m
Flow rate = 4 m 3 /s
Water density = 10 3 kg/m 3
Dynamic viscosity = 1.30710 -3 N.sec/m
Now,
At the minimum particular diameter it is stated as follows:
The Reynolds number= 0.1
Thus,
0.1 =ρVTD/μ
VT = Dp² ( ρp- ρ) g/ 10μ²
Where
gn = The case/issue of sedimentation
VT = Terminal velocity
So,
0.1 = Dp³ ( ρp- ρ) g/ 10μ²
This becomes,
0.1 = 1000 * dp³ (1100-1000) g 0.1/ 10 *(1.307 * 10 ^⁻3)²
= 3.074 * 10 ^⁻6 = dp³ (.g01 * 10^6)
dp³=3.1343 * 10 ^⁻12
Dp minimum= 1.474 * 10 ^⁻4 meters.
Answer:
The right solution is "28.45%".
Explanation:
The given values are:
and,
At 45,
⇒ 
At 
,
or,
then,
⇒ 
hence,
The isentropic efficiency of turbine will be:
⇒ 
(%)
The thermal efficiency of cycle will be:
⇒ 
(%)
