Answer:
The gplanet is 0.193 m/s^2
Explanation:
The speed of the pulse is:


where
m=mass of the wire=4 g= 4x10^-3 kg
M=mass of the object= 3 kg
Replacing values:

Answer:
We would not be able to make our way around the earth's surface, to read, to sculpt or to create technology because we cannot see!
Explanation:
The minimum angular separation that can be distinguished by an eye gives the angular resolution of the eye.
Given that the Angular resolution with infrared radiation is =
equal to 
This resolution is very much greater than that of the eye 
The angular resolution that our eyes can see is about
at arms length
Angular resolution of infrared =
at arms length
We therefore cannot read, sculpt or create technology because we cannot see.
hmax = 5740.48 m. The maximum height that a cannonball fired at 420 m/s at a 53.0° angles is 5740.48m.
This is an example of parabolic launch. A cannonball is fired on flat ground at 420 m/s at a 53.0° angle and we have to calculate the maximum height that it reach.
V₀ = 420m/s and θ₀ = 53.0°
So, when the cannonball is fired it has horizontal and vertical components:
V₀ₓ = V₀ cos θ₀ = (420m/s)(cos 53°) = 252.76 m/s
V₀y = V₀ cos θ₀ = (420m/s)(cos 53°) = 335.43m/s
When the cannoball reach the maximum height the vertical velocity component is zero, that happens in a tₐ time:
Vy = V₀y - g tₐ = 0
tₐ = V₀y/g
tₐ = (335.43m/s)/(9.8m/s²) = 34.23s
Then, the maximum height is reached in the instant tₐ = 34.23s:
h = V₀y tₐ - 1/2g tₐ²
hmax = (335.43m/s)(34.23s)-1/2(9.8m/s²)(34.23s)²
hmax = 11481.77m - 5741.29m
hmax = 5740.48m
Answer:
Explanation:
Formula and givens
- λ = c / f
- λ is the wavelength
- c = the speed of light
- f = the frequency
- c = 3*10^8
- f = 7.89 * 10^14
λ = ?
Solution
λ = 3*10^8 / 7.89*10^14
λ = 3*10^8/7.89*10^14
λ = 2.36 * 10^7
λ = 236 nanometers. What you use as your solution depends on what what you have been taught.
Answer:
Can enter or leave the system matter and energy. (The correct option is D)
Explanation:
Open system is defined as the system where exchange of matter, and energy occurs with its surrounding, presenting breaking down, and build up of its materials, and import, export of components.
Open system transfer the material into, and out of the system boundary, it contains an external interaction. A good example of open system is living things they actively connect with its environment, in results it shows changes in both the environment, and the living things.
So, the correct option is D.