a = ( v(2) - v(1) ) ÷ ( t(2) - t(1) )
2 = ( v(2) - 10 ) ÷ ( 6 - 0 )
2 × 6 = v(2) - 10
v(2) = 12 + 10
v(2) = 22 m/s
First of all, there are not <u>just</u> two applications that are solely applicable to the electron beam welding process. There are MANY.
Please visit out website at the URL below and you can click the "View Application" button under each listed Industry segment to view case studies of commonly EB welded applications.
https://www.ptreb.com/electron-beam-welding-applications
And for more general information on our welding process, we have an informational section you can peruse as well:
https://www.ptreb.com/electron-beam-welding-information
Good luck with your assignment- we are glad to hear they are teaching about EBW in high school!!!
Answer:
33. at the top?
34. to add more "energy" to the water and keep it moving
35. the dam because the energy is is building up
Explanation:
i tink that's correct sorry if not
have a good rest of ur day
Answer:
Their densities are different as well
Explanation:
Density is worked out by dividing mass by volume. If the mass was the same then the densities would be as well. But it's not.
How many marks is this question?
Answer:
E_Phase = 560V
Explanation:
The computation of the voltage i.e. dropped across each phase is shown below:
Given that
The delta connection line voltage is
E_line = 560 V
And, in the case of delta connection, the line voltage would be equivalent to the phase voltage
That means
E_Phase = E_Line
= 560 V
Hence, the voltage i.e. dropped across each phase is
E_Phase = 560V
