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Answer:
-0.73 m/s
Explanation:
We can solve this problem by using the law of conservation of momentum.
In fact, in absence of external forces (the ice is frictionless, so no friction), the total momentum of Aisha + two boots is conserved.
At the beginning, their total momentum is zero, since they are at rest:
(1)
After, their total momentum is:
(2)
where:
M is Aisha's mass
v is Aisha's velocity relative to the ground
m = 4.50 kg is the mass of each boot
v' is the boot's velocity relative to the ground
We can find:
is Aisha's mass (where W = 637 N was her weight)
v' can be rewritten as:
because 6 m/s is the velocity of the boots relative to her, while v' is their velocity relative to the ground.
Substituting and combining (1) and (2) we find:
and the negative sign indicates that the direction is opposite to that of the boots.