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slega [8]
3 years ago
13

How many grams of NaOH are needed to neutralize 50 grams of H2SO4

Chemistry
2 answers:
slavikrds [6]3 years ago
8 0

Answer:

H2SO4 + 2NaOH ==> Na2SO4 + 2H2O

Explanation:

Ede4ka [16]3 years ago
8 0
H2SO4 + 2NaOH ==> Na2SO4 + 2H2O

mols H2SO4 = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols H2SO4 to mols NaOH.
2Naoh+h2so4 na2so4+2h2o
50g/100g=x/98g
X=98g×50g/100g
X=49g
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How many seconds does it take a race horse to run six furlongs at 40.7 miles per hour if: I furlong = 40 rods; 5.5 yards = 1 rod
lana [24]

Distance traveled by the race horse=6 furlongs

Converting the distance from furlongs to rods: 40 rods =1 furlong

6 furlongs*\frac{40rods}{1furlong} =240rods

Converting the distance from rods to yards, feet and miles: 5.5 yards = 1 rod, 3foot =1 yard, 1 mile = 5280 feet.

240rods*\frac{5.5yards}{1rod}*\frac{3foot}{1yard}*\frac{1mi}{5280feet}=0.75mi

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0.75mi*\frac{1hr}{40.7mi}*\frac{60min}{1hr}*\frac{60s}{1min}= 66.34s

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8 0
3 years ago
Suppose the reaction between nitrogen and hydrogen was run according to the amounts presented in Part A, and the temperature and
andrew11 [14]

Explanation:

Assuming that moles of nitrogen present are 0.227 and moles of hydrogen are 0.681. And, initially there are 0.908 moles of gas particles.

This means that, for N_{2}(g) + 3H_{2}(g) \rightarrow 2NH_{3}

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As it is known that the ideal gas equation  is PV = nRT

And, as the temperature and volume were kept constant, so we can write

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       P_(final) = 10.4 \times \frac{0.454}{0.908}

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Therefore, we can conclude that the expected pressure after the reaction was completed is 5.2 atm.

7 0
3 years ago
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